feat: Normalize whitespace by removing extra spaces from a string

- Input: String containing irregular and excessive whitespace between words.
  Example: "               abc    de      fgh        ijk"
- Used `str.replaceAll("\\s+", " ")` to:
  - Match and replace one or more whitespace characters (`\\s+`) with a single space.
- Applied `.trim()` to remove leading and trailing spaces from the result.

🔍 Explanation:
- `\\s` matches any whitespace character (space, tab, newline).
- `\\s+` matches a sequence of one or more whitespace characters.
- `trim()` ensures no leftover spaces at the beginning or end.

🧪 Output:
- Before: `"               abc    de      fgh        ijk"`
- After: `"abc de fgh ijk"`

✅ Useful for cleaning and formatting user input, logs, or data for storage/display.

Signed-off-by: Somesh diwan <[email protected]>

Author: Someshdiwan

Section6StringClassPrinting/src/RegularExpressionChallenge4.java

@@ -1,13 +1,14 @@
-/*
-Remove extra spaces from string
-Logic:  String str = "abc      de       fgh           ijk"
-Method used here: str.ReplaceAll("\\s", " ");
-Small s means space & Capital S means not a space.
-*/
-
 public class RegularExpressionChallenge4 {
     public static void main(String[] args) {
         String str = "               abc    de      fgh        ijk";
         System.out.println(str.replaceAll("\\s+", " ").trim());
     }
-}
+}
+
+/*
+Remove extra spaces from string.
+Logic:  String str = "abc      de       fgh           ijk"
+
+Method used here: str.ReplaceAll("\\s", " ");
+Small s means space & Capital S means not a space.
+*/