feat: Count the number of digits in a given number

🧠 Logic:
- Take integer input `n`.
- Initialize counter `count = 0`.
- Use a `while` loop to repeatedly divide `n` by 10.
  - Each division removes the last digit.
  - Increment `count` on each iteration.
- When `n` becomes 0, `count` holds the total number of digits.

Signed-off-by: Somesh diwan <[email protected]>

Author: Someshdiwan

Section8LoopAB/src/CountDigitsOfNumbers.java

@@ -8,8 +8,7 @@ public static void main(String[] args) {
         int n = scan.nextInt();
 
         int count = 0;
-
-        while(n>0){
+        while(n>0) {
             n = n/10;
             count++;
         }