feat: Check if a number is an Armstrong number with digit-wise cube breakdown

🧠 Logic:
- Read integer input from the user.
- Store the original number to compare later.
- Loop through each digit of the number:
  - Extract last digit using `% 10`.
  - Calculate its cube and add to running sum.
  - Print the digit and its cube for traceability.
- After loop, compare sum of cubes with original number:
  - If equal, it is an Armstrong number.

Signed-off-by: Somesh diwan <[email protected]>

Author: Someshdiwan

Section8LoopAB/src/ArmNumber.java

@@ -0,0 +1,35 @@
+import java.util.Scanner;
+
+public class ArmNumber {
+    public static void main(String[] args) {
+        Scanner scanner = new Scanner(System.in);
+
+        System.out.print("Enter a number: ");
+        int number = scanner.nextInt();
+
+        int originalNumber = number;
+        int sum = 0;
+
+        System.out.println("\nCalculating sum of cubes of digits:");
+        System.out.println("-----------------------------------");
+
+        while (number > 0) {
+            int digit = number % 10;
+            int cube = digit * digit * digit;
+
+            System.out.printf("Digit: %d, Cube: %d%n", digit, cube);
+
+            sum += cube;
+            number = number / 10;
+        }
+
+        System.out.println("-----------------------------------");
+        System.out.println("Total sum: " + sum);
+
+        if (sum == originalNumber) {
+            System.out.println(originalNumber + " is an Armstrong number!");
+        }
+
+        scanner.close();
+    }
+}