feat: Implement logic to reverse a given number using modulus and division

🧠 Logic:
- Extract digits from the number using `% 10`.
- Build the reversed number by multiplying `rev` by 10 and adding the digit.
- Repeat until the original number becomes 0.
- Print the reversed number at the end.

Signed-off-by: Somesh diwan <[email protected]>

Author: Someshdiwan

Section8LoopAB/src/ReverseANumber.java

@@ -1,5 +1,3 @@
-//Reverse a number.
-
 import java.util.Scanner;
 
 public class ReverseANumber {
@@ -9,8 +7,7 @@ public static void main(String[] args) {
         int n = sc.nextInt();
 
         int rev =0,r;
-        while (n>0)
-        {
+        while (n>0) {
             r=n%10;
             rev=rev*10+r;
             n/=10;