Is there a way to determine if a cell was defined via an accessor column, i.e. not a display column

[writes-of-spring]

Working on a data export on a table with row selection.
Checkbox is a display column, I'm wondering if there's a way to easily exclude this column when I'm mapping over the the visible cells for each row?

Thanks!

[theMattCode]

Would it be an option to use getSelectedRowModel when working with the data itself?

[writes-of-spring]

getSelectedRowModel doesn't take into account column visibility,

My code at present is

const rows = table.getSelectedRowModel()
 const visRows = rows.map((row) => {
    const [cell1, ...otherCells] = row
      .getVisibleCells()
      .filter((cell) => cell.column.id !== "actions")
      .map((cell) => {
        const getExportedValue = cell.column.columnDef.meta?.getExportedValue;
        return getExportedValue?.(cell) ?? cell.getValue();
      });
    return [cell1, "", ...otherCells];

this use case is made slightly more awkward because it involves injecting a column into the pdf table export, so a bespoke filter is fine.

but was wondering if there's a better / more general way!

Thanks