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| 1 | +/** |
| 2 | + * @file |
| 3 | + * @brief Given an integer array nums and an integer k, split nums into k |
| 4 | + * non-empty subarrays such that the largest sum of any subarray is minimized. |
| 5 | + * Return the minimized largest sum of the split. |
| 6 | +
|
| 7 | + * @details |
| 8 | + * Example 1: |
| 9 | +
|
| 10 | + * Input: nums = [7,2,5,10,8], k = 2 |
| 11 | + * Output: 18 |
| 12 | + * Explanation: There are four ways to split nums into two subarrays. |
| 13 | + * The best way is to split it into [7,2,5] and [10,8], where the largest sum |
| 14 | + * among the two subarrays is only 18. |
| 15 | + |
| 16 | + * Example 2: |
| 17 | +
|
| 18 | + * Input: nums = [1,2,3,4,5], k = 2 |
| 19 | + * Output: 9 |
| 20 | + * Explanation: There are four ways to split nums into two subarrays. |
| 21 | + * The best way is to split it into [1,2,3] and [4,5], where the largest sum |
| 22 | + * among the two subarrays is only 9. |
| 23 | +
|
| 24 | + * @author [ARYA PRATAP SINGH](https://github.com/ARYPROGRAMMER) |
| 25 | + * [Leetcode](https://leetcode.com/problems/split-array-largest-sum/description/?envType=problem-list-v2&envId=dynamic-programming) |
| 26 | + */ |
| 27 | + |
| 28 | +// header files |
| 29 | +#include <iostream> |
| 30 | +#include <iomanip> |
| 31 | +#include <cstdint> |
| 32 | + |
| 33 | +/** |
| 34 | + * @namespace dynamic_programming |
| 35 | + * @brief Dynamic Programming algorithms |
| 36 | + */ |
| 37 | +namespace dynamic_programming{ |
| 38 | + /** |
| 39 | + * @namespace split_array_largest_sum |
| 40 | + * @brief split_array_largest_sum algorithm |
| 41 | + */ |
| 42 | + namespace split_array_largest_sum{ |
| 43 | + |
| 44 | + /** |
| 45 | + * @brief This function calculates the minimum largest sum of the split |
| 46 | + * @param nums integer array |
| 47 | + * @param k integer |
| 48 | + * @ |
| 49 | + */ |
| 50 | + |
| 51 | + int dp[1003][53]; |
| 52 | + |
| 53 | + int f(int i, int j, vector<int>& v) { |
| 54 | + if (j < 0) { |
| 55 | + if (i < 0) |
| 56 | + return -1; |
| 57 | + return INT_MAX; |
| 58 | + } |
| 59 | + if (i < 0) |
| 60 | + return INT_MAX; |
| 61 | + if (dp[i][j] != -1) |
| 62 | + return dp[i][j]; |
| 63 | + |
| 64 | + int res = INT_MAX, sum = 0; |
| 65 | + for (int k = i; k >= 0; k--) { |
| 66 | + sum += v[k]; |
| 67 | + res = min(res, max(sum, f(k - 1, j - 1, v))); |
| 68 | + } |
| 69 | + |
| 70 | + return dp[i][j] = res; |
| 71 | + } |
| 72 | + |
| 73 | + int splitArray(vector<int>& nums, int k) { |
| 74 | + memset(dp, -1, sizeof(dp)); |
| 75 | + return f(nums.size() - 1, k - 1, nums); |
| 76 | + } |
| 77 | + } |
| 78 | +} |
| 79 | + |
| 80 | +/** |
| 81 | + * Test Function |
| 82 | + * @return void |
| 83 | + */ |
| 84 | +static void test() { |
| 85 | + // custom input vector |
| 86 | + std::vector<int> v{ |
| 87 | + 7,2,5,10,8,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15 |
| 88 | + }; |
| 89 | + // custom value of k |
| 90 | + int k = 5; |
| 91 | + |
| 92 | + //calling the function |
| 93 | + int ans = dynamic_programming::split_array_largest_sum::splitArray(v, k); |
| 94 | + |
| 95 | + // expected output |
| 96 | + int expectedOutput = 30; |
| 97 | + |
| 98 | + // Testing implementation via assert function |
| 99 | + // It will throw error if any of the expected test fails |
| 100 | + // Else it will give nothing |
| 101 | + assert(ans == expectedOutput); |
| 102 | + |
| 103 | + std::cout << "All tests passed successfully!\n"; |
| 104 | + return; |
| 105 | +} |
| 106 | + |
| 107 | +/** Main function (driver code)*/ |
| 108 | +int main() { |
| 109 | + // test for implementation |
| 110 | + test(); |
| 111 | + |
| 112 | + // user input |
| 113 | + int n; |
| 114 | + std::cout << "Enter the number of elements in the array : "; |
| 115 | + std::cin >> n; |
| 116 | + std::vector<int> v(n); |
| 117 | + std::cout << "Enter the elements of the array : "; |
| 118 | + for (int i = 0; i < n; i++) { |
| 119 | + std::cin >> v[i]; |
| 120 | + } |
| 121 | + int k; |
| 122 | + std::cout << "Enter the value of k : "; |
| 123 | + std::cin >> k; |
| 124 | + |
| 125 | + int ans; |
| 126 | + |
| 127 | + // user output |
| 128 | + ans = dynamic_programming::split_array_largest_sum::splitArray(v, k); |
| 129 | + std::cout << "The minimum largest sum of the split is : " << ans << std::endl; |
| 130 | + return 0; |
| 131 | +} |
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