diff --git a/leetcode/src/15.c b/leetcode/src/15.c
new file mode 100644
index 0000000000..1993b2f42e
--- /dev/null
+++ b/leetcode/src/15.c
@@ -0,0 +1,77 @@
+// Function to compare two integers for qsort
+// This function is used to sort the array by comparing two integer values.
+int compare(const void* a, const void* b) { return (*(int*)a - *(int*)b); }
+
+// Function to find all unique triplets in the array that sum to zero
+// This function uses sorting and a two-pointer approach to find triplets
+// in a given array that add up to zero, ensuring no duplicate triplets are
+// returned. The result is dynamically allocated and returned, along with column
+// sizes and the total number of triplets found.
+int** threeSum(int* nums, int numsSize, int* returnSize,
+               int** returnColumnSizes)
+{
+    if (numsSize < 3)
+    {
+        *returnSize = 0;
+        return NULL;
+    }
+
+    // Sort the array
+    qsort(nums, numsSize, sizeof(int), compare);
+
+    int** result = (int**)malloc(numsSize * numsSize * sizeof(int*));
+    *returnColumnSizes = (int*)malloc(numsSize * sizeof(int));
+    *returnSize = 0;
+
+    // Iterate through each element as the first element of the triplet
+    for (int i = 0; i < numsSize - 2; ++i)
+    {
+        if (i > 0 && nums[i] == nums[i - 1])
+        {
+            continue;  // Skip duplicates for the first number
+        }
+
+        int left = i + 1;
+        int right = numsSize - 1;
+
+        // Two-pointer approach to find the second and third elements
+        while (left < right)
+        {
+            int sum = nums[i] + nums[left] + nums[right];
+
+            if (sum == 0)
+            {
+                // Store the triplet
+                result[*returnSize] = (int*)malloc(3 * sizeof(int));
+                result[*returnSize][0] = nums[i];
+                result[*returnSize][1] = nums[left];
+                result[*returnSize][2] = nums[right];
+                (*returnColumnSizes)[*returnSize] = 3;
+                (*returnSize)++;
+
+                // Skip duplicates for the second and third numbers
+                while (left < right && nums[left] == nums[left + 1])
+                {
+                    left++;
+                }
+                while (left < right && nums[right] == nums[right - 1])
+                {
+                    right--;
+                }
+
+                left++;
+                right--;
+            }
+            else if (sum < 0)
+            {
+                left++;
+            }
+            else
+            {
+                right--;
+            }
+        }
+    }
+
+    return result;
+}