Update recursive_digit_sum.py

Author: sharath4444

recursions/recursive_digit_sum.py

@@ -1 +1,61 @@
+"""
+We define super digit of an integer x using the following rules:
 
+Given an integer, we need to find the super digit of the integer.
+
+If  has only 1 digit, then its super digit is x .
+Otherwise, the super digit of x is equal to the super digit of the sum of the digits of .
+For example, the super digit 9875 of  will be calculated as:
+
+	super_digit(9875)   	9+8+7+5 = 29 
+	super_digit(29) 	2 + 9 = 11
+	super_digit(11)		1 + 1 = 2
+	super_digit(2)		= 2 
+
+
+ ex -2:
+ Here n=148  and k=3 , so p=148148148 .
+
+super_digit(P) = super_digit(148148148) 
+               = super_digit(1+4+8+1+4+8+1+4+8)
+               = super_digit(39)
+               = super_digit(3+9)
+               = super_digit(12)
+               = super_digit(1+2)
+               = super_digit(3)
+               = 3
+ """
+
+
+"""
+
+Sample Input 0
+148 3
+
+Sample Output 0
+
+3
+
+"""
+def superDigit(n, k):
+    # Calculate the initial sum of the digits in n
+    digit_sum = sum(int(digit) for digit in n)
+    
+    # Multiply the sum by k
+    total_sum = digit_sum * k
+    
+    # Recursive function to find the super digit
+    while total_sum >= 10:
+        total_sum = sum(int(digit) for digit in str(total_sum))
+    
+    return total_sum
+
+if __name__ == '__main__':
+    first_multiple_input = input().rstrip().split()
+    
+    n = first_multiple_input[0]
+    k = int(first_multiple_input[1])
+    
+    result = superDigit(n, k)
+    
+    print(result)