Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack(); stack.push(1); stack.push(2); stack.top(); // returns 2 stack.pop(); // returns 2 stack.empty(); // returns false
Notes:
- You must use only standard operations of a queue -- which means only
push to back,peek/pop from front,size, andis emptyoperations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
Similar Questions:
// OJ: https://leetcode.com/problems/implement-stack-using-queues
// Author: github.com/lzl124631x
// Time: O(N) for push, O(1) for others
// Space: O(1)
class MyStack {
private:
queue<int> q;
public:
MyStack() {}
void push(int x) {
q.push(x);
for (int i = 0; i < q.size() - 1; ++i) {
q.push(q.front());
q.pop();
}
}
int pop() {
int val = q.front();
q.pop();
return val;
}
int top() {
return q.front();
}
bool empty() {
return q.empty();
}
};// OJ: https://leetcode.com/problems/implement-stack-using-queues/
// Author: github.com/lzl124631x
// Time: O(N) for pop, O(1) for others
// Space: O(1)
class MyStack {
queue<int> q;
int t;
public:
MyStack() {}
void push(int x) {
q.push(x);
t = x;
}
int pop() {
int n = q.size();
while (--n) {
int val = q.front();
if (n == 1) t = val;
q.push(val);
q.pop();
}
int val = q.front();
q.pop();
return val;
}
int top() {
return t;
}
bool empty() {
return !q.size();
}
};