Add Linear Search in Ruby (#5170)

Author: Elvin-code-dev

archive/r/ruby/linear-search.rb

@@ -0,0 +1,53 @@
+USAGE = 'Usage: please provide a list of integers ("1, 4, 5, 11, 12") and the integer to find ("11")'
+
+
+    if ARGV.length < 2
+        puts USAGE
+        return
+    end
+    
+    # the first input (list of numbers)
+    list_input = ARGV[0]
+    #second input (number to find)
+    target_input = ARGV[1]
+
+    #check if the input is empty
+    if list_input.strip.empty? || target_input.strip.empty?
+        puts USAGE
+        return
+    end
+
+    begin
+        #split list by the commas, trim the spaces, then turn into intgers
+        numbers = list_input.split(',').map { |s| s.strip.to_i }
+
+        #convert second number to integer
+        target = Integer(target_input)
+    rescue ArgumentError
+        # if conversion fails we show the usage message
+        puts USAGE
+        return
+    end
+
+    #track if we find the number
+    found = false
+
+    # go through each number in the list
+    numbers.each do |n|
+        if n == target
+            found = true
+            # stop searching once we find it
+            break
+        end
+    end
+
+    # print result as true or false
+    if found
+        puts "true"
+    else
+        puts "false"
+    end
+
+
+
+