@@ -193,52 +193,6 @@ $\delta = (m + \frac{1}{2}) \cdot \lambda$.
193193| 10 | Finding the distance to the bright spots | $y_b = m\frac{L\lambda}{d}$ |
194194| 11 | Finding the distance to the dark spots | $y_d = \left(m + \frac{1}{2}\right)\frac{L\lambda}{d}$ |
195195
196- 1 . Wavelength <br >
197- $\lambda = 2\pi / k$, <br >
198- where $\lambda$ = wavelength and k is a constant
199-
200-
201- 2 . Path Difference <br >
202- $\delta = r_2 - r_1$, <br >
203- where $\delta$ is path difference and r is the length of path
204-
205-
206- 3 . Square of Longer Source <br >
207- $r_2^2 = r^2 + \left(\frac{d}{2}\right)^2 - 2r\left(\frac{d}{2}\right)\cos\left(\frac{\pi}{2} - \theta\right) = r^2 + \left(\frac{d}{2}\right)^2 + dr\sin\theta$, <br >
208- where d is the distance from source to screen
209-
210-
211- 4 . Square of Shorter Source <br >
212- $r_1^2 = r^2 + \left(\frac{d}{2}\right)^2 - 2r\left(\frac{d}{2}\right)\cos\left(\frac{\pi}{2} + \theta\right) = r^2 + \left(\frac{d}{2}\right)^2 - dr\sin\theta$
213-
214-
215- 5 . Derivation from 3 - 4 <br >
216- $(r_2 - r_1)(r_2 + r_1) = 2dr\sin\theta$
217-
218-
219- 6 . Small distance approximation <br >
220- $\delta = r_2 - r_1 \approx d\sin\theta$
221-
222-
223- 7 . Condition for constructive interference <br >
224- $d\sin\theta = m\lambda, \quad m = 0, \pm1, \pm2, \pm3, \ldots \text{ (constructive interference)}$
225-
226-
227- 8 . Condition for destructive interference <br >
228- $d\sin\theta = \left(m + \frac{1}{2}\right)\lambda, \quad m = 0, \pm1, \pm2, \pm3, \ldots \text{ (destructive interference)}$
229-
230-
231- 9 . Small Angle Approximation <br >
232- $\sin\theta \approx \tan\theta = \frac{y}{L}$
233-
234-
235- 10 . Finding the distance to the bright spots <br >
236- $y_b = m\frac{L\lambda}{d}$
237-
238-
239- 11 . Finding the distance to the dark spots <br >
240- $y_d = \left(m + \frac{1}{2}\right)\frac{L\lambda}{d}$
241-
242196
243197## Enrichment:
244198
0 commit comments