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BinarySearch.java
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44 lines (32 loc) · 1.07 KB
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public class BinarySearch {
// Recursive Binary Search by JAVA
public static void main(String args[])
{
BinarySearch ob = new BinarySearch();
int arr[] = { 20, 13, 4, 11, 40 };
int n = arr.length;
int x = 11;
int result = ob.binarySearch(arr, 0, n - 1, x);
if (result == -1)
System.out.println("Element not present");
else
System.out.println("Element found at index " + result+".");
System.out.println("Element is at " + (result+1)+" position.");
}
int binarySearch(int arr[], int l, int r, int x)
{
if (r >= l) {
int mid = l + (r - l) / 2;
// If element is present at the middle itself
if (arr[mid] == x)
return mid;
// If element is smaller than mid, then it can only be present in left subarray
if (arr[mid] > x)
return binarySearch(arr, l, mid - 1, x);
// Else the element can only be present in right subarray
return binarySearch(arr, mid + 1, r, x);
}
// We reach here when element is not present in array
return -1;
}
}