|
| 1 | +# Simple script to calculate the number of variants per year |
| 2 | + |
| 3 | +import sys |
| 4 | +import pandas as pd |
| 5 | + |
| 6 | + |
| 7 | +def get_total(s): |
| 8 | + """Convert a semicolon-separated list of integers into the sum of that list. |
| 9 | +
|
| 10 | + Helper function for multi-target papers. |
| 11 | +
|
| 12 | + Returns the integer if only one value is present. |
| 13 | +
|
| 14 | + Returns 0 if the value of s is None or NA. |
| 15 | + """ |
| 16 | + if s is None or pd.isna(s): |
| 17 | + return 0 |
| 18 | + elif ";" in s: |
| 19 | + return sum(int(x) for x in s.split(";")) |
| 20 | + else: |
| 21 | + return int(s) |
| 22 | + |
| 23 | + |
| 24 | +if __name__ == "__main__": |
| 25 | + # read the table |
| 26 | + if len(sys.argv) > 1: |
| 27 | + infile = sys.argv[1] |
| 28 | + else: |
| 29 | + infile = "maverefs.tsv" |
| 30 | + df = pd.read_csv(infile, sep="\t") |
| 31 | + |
| 32 | + # calculate and store the number of variants per paper |
| 33 | + # keep the maximum of nt and aa variant counts if both are specified |
| 34 | + df["Variants (max)"] = 0 |
| 35 | + for i, r in df.iterrows(): |
| 36 | + df.loc[i, "Variants (max)"] = max( |
| 37 | + get_total(r["Variants (nt)"]), get_total(r["Variants (aa)"]) |
| 38 | + ) |
| 39 | + |
| 40 | + # calculate the sum of variants for each year |
| 41 | + result = df.groupby("Year")["Variants (max)"].sum() |
| 42 | + result.index = [ |
| 43 | + int(x) for x in result.index |
| 44 | + ] # convert years to ints instead of float |
| 45 | + result.index.name = "year" |
| 46 | + result.name = "variants" |
| 47 | + result = pd.DataFrame(result) |
| 48 | + result["cumulative_variants"] = result["variants"].cumsum() |
| 49 | + |
| 50 | + # write the result to stdout |
| 51 | + result.to_csv(sys.stdout) |
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