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+# Maximum Circular Sum
+This question involves the usage of an algorithm known as Kadane's Algorithm
+## Question
+You are provided n numbers (both +ve and -ve). Numbers are arranged in a circular form. You need to find the maximum sum of consecutive numbers.
+```
+Input Format
+First line contains integer t which is number of test case.
+For each test case, it contains an integer n which is the size of array and next line contains n space separated integers denoting the elements of the array.
+
+Constraints
+1<=t<=100
+1<=n<=1000
+|Ai| <= 10000
+
+Output Format
+Print the maximum circular sum for each testcase in a new line.
+```
+
+## Code
+```
+#include<iostream>
+#include<climits>
+using namespace std;
+
+int main()
+{
+    int n; cin>>n;
+    int i,arr[n];
+    for(i=0; i<n; i++) cin>>arr[i];
+    int maxSum=INT_MIN, minSum=INT_MAX, currsum1=0, currsum2=0;
+    int TotalSum=0;
+    for (i=0; i<n; i++){
+        TotalSum+=arr[i]; currsum1+=arr[i]; currsum2+=arr[i];
+        if (currsum1>maxSum) maxSum=currsum1;
+        if (currsum2<minSum) minSum=currsum2;
+        if (currsum1<0) currsum1=0;
+        if (currsum2>0) currsum2=0;
+    }
+    if (minSum==TotalSum) cout<<maxSum;
+    else {
+        if (maxSum > TotalSum-minSum) cout<<maxSum;
+        else cout<<TotalSum-minSum;
+    }
+    
+    return 0;
+} 
+```
+## Sample Test Case
+```
+Input
+1
+7
+8 -8 9 -9 10 -11 12
+Output
+22
+
+Explanation
+Maximum Circular Sum = 22 (12 + 8 - 8 + 9 - 9 + 10)
+```