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Add tests for LicenseWithExceptionSymbol python operators
Signed-off-by: Aaron Bassett <[email protected]>
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tests/test_license_expression.py

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@@ -96,6 +96,42 @@ def test_LicenseSymbol(self):
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# symbol euqality is based ONLY on the key
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assert sym5 == sym6
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def test_python_operators_simple(self):
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licensing = Licensing()
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sym1 = LicenseSymbol('MIT')
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sym2 = LicenseSymbol('BSD-2')
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assert sym1 & sym2 == licensing.AND(sym1, sym2)
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assert sym1 | sym2 == licensing.OR(sym1, sym2)
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sym3 = LicenseWithExceptionSymbol(LicenseSymbol("GPL-3.0-or-later"), LicenseSymbol("GCC-exception-3.1"))
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# Make sure LicenseWithExceptionSymbol operation work on left and right side
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assert sym3 & sym1 == licensing.AND(sym3, sym1)
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assert sym1 & sym3 == licensing.AND(sym1, sym3)
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assert sym3 | sym1 == licensing.OR(sym3, sym1)
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assert sym1 | sym3 == licensing.OR(sym3, sym1)
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def test_boolean_expression_operators(self):
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# Make sure LicenseWithExceptionSymbol boolean expression are set
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assert LicenseWithExceptionSymbol.Symbol is not None
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assert LicenseWithExceptionSymbol.TRUE is not None
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assert LicenseWithExceptionSymbol.FALSE is not None
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assert LicenseWithExceptionSymbol.AND is not None
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assert LicenseWithExceptionSymbol.OR is not None
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assert LicenseWithExceptionSymbol.NOT is not None
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# Make sure LicenseWithExceptionSymbol matches LicenseSymbol
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assert LicenseWithExceptionSymbol.Symbol == LicenseSymbol
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assert LicenseWithExceptionSymbol.TRUE == LicenseSymbol.TRUE
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assert LicenseWithExceptionSymbol.FALSE == LicenseSymbol.FALSE
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assert LicenseWithExceptionSymbol.AND == LicenseSymbol.AND
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assert LicenseWithExceptionSymbol.OR == LicenseSymbol.OR
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assert LicenseWithExceptionSymbol.NOT == LicenseSymbol.NOT
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class LicensingTest(TestCase):
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