Only check the savings if a word occurs at least twice

Profiling shows that `est_net_savings` is one of the highest costs of
the whole process. Approximately, you can save storage only if a word
appears more than once, and doing this greatly reduces the number
of `est_net_savings` calls. Locally, it reduces the time for this
specific build step by 50% on ports/unix coverage build, without
affecting the size of the generated binary.

Author: jepler

py/makeqstrdata.py

@@ -400,7 +400,8 @@ def est_net_savings(s, occ):
         # words[] array.
 
         scores = sorted(
-            ((s, -est_net_savings(s, occ)) for (s, occ) in counter.items()), key=lambda x: x[1]
+            ((s, -est_net_savings(s, occ)) for (s, occ) in counter.items() if occ > 1),
+            key=lambda x: x[1],
         )
 
         # Pick the one with the highest score.  The score must be negative.