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d fix linking errors in javadoc
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approvaltests-util/src/main/java/org/lambda/query/Query.java

Lines changed: 4 additions & 4 deletions
Original file line numberDiff line numberDiff line change
@@ -113,14 +113,14 @@ public static <T> Queryable<T> orderBy(List<T> list, Order order, Function1<T, C
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return Queryable.as(list);
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}
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/**
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* Why does sum() return double? see {@link #sum(Out[])}
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* Why does sum() return double? see {@link #sum(Number[])}
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*/
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public static <In, Out extends Number> Double sum(In[] list, Function1<In, Out> f1)
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{
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return sum(ArrayUtils.asList(list), f1);
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}
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/**
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* Why does sum() return double? see {@link #sum(Out[])}
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* Why does sum() return double? see {@link #sum(Number[])}
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*/
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public static <In, Out extends Number> Double sum(Collection<In> list, Function1<In, Out> f1)
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{
@@ -132,7 +132,7 @@ public static <In, Out extends Number> Double sum(Collection<In> list, Function1
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return sum;
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}
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/**
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* Why does sum() return double? see {@link #sum(Out[])}
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* Why does sum() return double? see {@link #sum(Number[])}
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*/
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public static <Out extends Number> Double sum(Collection<Out> list)
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{
@@ -142,7 +142,7 @@ public static <Out extends Number> Double sum(Collection<Out> list)
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* <H1>Why does sum() return double?</H1><br>
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* sum() needs to handle possible overflow.<br>
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* For example:<br>
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* <code>Queryable.as(100, 100, 100).sum(n -> n.byteValue())</code> should equal 300.<br>
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* <code>Queryable.as(100, 100, 100).sum(n -&gt; n.byteValue())</code> should equal 300.<br>
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* Because Double handles the largest range of any number, that is what is returned by default. You can convert
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* it to whichever type you want, but be aware that overflowed values may be truncated.
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*/

approvaltests-util/src/main/java/org/lambda/query/Queryable.java

Lines changed: 1 addition & 1 deletion
Original file line numberDiff line numberDiff line change
@@ -79,7 +79,7 @@ public Queryable<In> orderBy(Order order, Function1<In, Comparable<?>> f1)
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return Query.orderBy(this, order, f1);
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}
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/**
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* Why does sum() return double? see {@link org.lambda.query.Query#sum(Out[])}
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* Why does sum() return double? see {@link org.lambda.query.Query#sum(Number[])}
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*/
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public <Out extends Number> Double sum(Function1<In, Out> f1)
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{

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