Update api_sqs_lambda_stack.py -- fix the python 3.7 unsupported problem

pikachuSparkle · web-flow · commit 534260ebda22 · 2025-06-09T14:30:40.000+08:00
"The runtime parameter of python3.7 is no longer supported for creating or updating AWS Lambda functions. "
diff --git a/python/api-sqs-lambda/api_sqs_lambda/api_sqs_lambda_stack.py b/python/api-sqs-lambda/api_sqs_lambda/api_sqs_lambda_stack.py
@@ -69,7 +69,7 @@ def __init__(self, scope: Construct, id: str, **kwargs) -> None:
         #Creating Lambda function that will be triggered by the SQS Queue
         sqs_lambda = _lambda.Function(self,'SQSTriggerLambda',
             handler='lambda-handler.handler',
-            runtime=_lambda.Runtime.PYTHON_3_7,
+            runtime=_lambda.Runtime.PYTHON_3_11,
             code=_lambda.Code.from_asset('lambda'),
         )
 

Original file line number	Diff line number	Diff line change
`@@ -69,7 +69,7 @@ def __init__(self, scope: Construct, id: str, **kwargs) -> None:`
`69`	`69`	`#Creating Lambda function that will be triggered by the SQS Queue`
`70`	`70`	`sqs_lambda = _lambda.Function(self,'SQSTriggerLambda',`
`71`	`71`	`handler='lambda-handler.handler',`
`72`		`- runtime=_lambda.Runtime.PYTHON_3_7,`
	`72`	`+ runtime=_lambda.Runtime.PYTHON_3_11,`
`73`	`73`	`code=_lambda.Code.from_asset('lambda'),`
`74`	`74`	`)`
`75`	`75`