explicitly label the url as the launch url

Author: Hweinstock

src/ec2/commands.ts

@@ -50,7 +50,7 @@ export async function rebootInstance(node?: Ec2Node) {
 
 export async function linkToLaunchInstance(node?: Ec2Node) {
     const region = node ? node.regionCode : globals.regionProvider.guessDefaultRegion()
-    const url = getAwsConsoleUrl('ec2', region)
+    const url = getAwsConsoleUrl('ec2-launch', region)
     await openUrl(url)
 }
 

src/shared/awsConsole.ts

@@ -5,13 +5,13 @@
 
 import * as vscode from 'vscode'
 
-export function getAwsConsoleUrl(service: 'ecr' | 'cloudformation' | 'ec2', region: string): vscode.Uri {
+export function getAwsConsoleUrl(service: 'ecr' | 'cloudformation' | 'ec2-launch', region: string): vscode.Uri {
     switch (service) {
         case 'ecr':
             return vscode.Uri.parse(`https://${region}.console.aws.amazon.com/ecr/repositories?region=${region}`)
         case 'cloudformation':
             return vscode.Uri.parse(`https://${region}.console.aws.amazon.com/cloudformation/home?region=${region}`)
-        case 'ec2':
+        case 'ec2-launch':
             return vscode.Uri.parse(
                 `https://${region}.console.aws.amazon.com/ec2/home?region=${region}#LaunchInstances:`
             )