Change tags to avoid collisions with earlier draft

Author: sipa

bip-0340.mediawiki

@@ -147,13 +147,13 @@ The algorithm ''Sign(sk, m)'' is defined as:
 * Fail if ''d' = 0'' or ''d' ≥ n''
 * Let ''P = d'⋅G''
 * Let ''d = d' '' if ''has_even_y(P)'', otherwise let ''d = n - d' ''.
-* Let ''t'' be the byte-wise xor of ''bytes(d)'' and ''hash<sub>BIP340/aux</sub>(a)''<ref>The auxiliary random data is hashed (with a unique tag) as a precaution against situations where the randomness may be correlated with the private key itself. It is xored with the private key (rather than combined with it in a hash) to reduce the number of operations exposed to the actual secret key.</ref>.
-* Let ''rand = hash<sub>BIP340/nonce</sub>(t || bytes(P) || m)''<ref>Including the [https://moderncrypto.org/mail-archive/curves/2020/001012.html public key as input to the nonce hash] helps ensure the robustness of the signing algorithm by preventing leakage of the secret key if the calculation of the public key ''P'' is performed incorrectly or maliciously, for example if it is left to the caller for performance reasons.</ref>.
+* Let ''t'' be the byte-wise xor of ''bytes(d)'' and ''hash<sub>BIP0340/aux</sub>(a)''<ref>The auxiliary random data is hashed (with a unique tag) as a precaution against situations where the randomness may be correlated with the private key itself. It is xored with the private key (rather than combined with it in a hash) to reduce the number of operations exposed to the actual secret key.</ref>.
+* Let ''rand = hash<sub>BIP0340/nonce</sub>(t || bytes(P) || m)''<ref>Including the [https://moderncrypto.org/mail-archive/curves/2020/001012.html public key as input to the nonce hash] helps ensure the robustness of the signing algorithm by preventing leakage of the secret key if the calculation of the public key ''P'' is performed incorrectly or maliciously, for example if it is left to the caller for performance reasons.</ref>.
 * Let ''k' = int(rand) mod n''<ref>Note that in general, taking a uniformly random 256-bit integer modulo the curve order will produce an unacceptably biased result. However, for the secp256k1 curve, the order is sufficiently close to ''2<sup>256</sup>'' that this bias is not observable (''1 - n / 2<sup>256</sup>'' is around ''1.27 * 2<sup>-128</sup>'').</ref>.
 * Fail if ''k' = 0''.
 * Let ''R = k'⋅G''.
 * Let ''k = k' '' if ''has_even_y(R)'', otherwise let ''k = n - k' ''.
-* Let ''e = int(hash<sub>BIP340/challenge</sub>(bytes(R) || bytes(P) || m)) mod n''.
+* Let ''e = int(hash<sub>BIP0340/challenge</sub>(bytes(R) || bytes(P) || m)) mod n''.
 * Let ''sig = bytes(R) || bytes((k + ed) mod n)''.
 * If ''Verify(bytes(P), m, sig)'' (see below) returns failure, abort<ref>Verifying the signature before leaving the signer prevents random or attacker provoked computation errors. This prevents publishing invalid signatures which may leak information about the secret key. It is recommended, but can be omitted if the computation cost is prohibitive.</ref>.
 * Return the signature ''sig''.
@@ -182,7 +182,7 @@ The algorithm ''Verify(pk, m, sig)'' is defined as:
 * Let ''P = lift_x_even_y(int(pk))''; fail if that fails.
 * Let ''r = int(sig[0:32])''; fail if ''r &ge; p''.
 * Let ''s = int(sig[32:64])''; fail if ''s &ge; n''.
-* Let ''e = int(hash<sub>BIP340/challenge</sub>(bytes(r) || bytes(P) || m)) mod n''.
+* Let ''e = int(hash<sub>BIP0340/challenge</sub>(bytes(r) || bytes(P) || m)) mod n''.
 * Let ''R = s⋅G - e⋅P''.
 * Fail if ''not has_even_y(R)'' or ''x(R) &ne; r''.
 * Return success iff no failure occurred before reaching this point.
@@ -205,7 +205,7 @@ The algorithm ''BatchVerify(pk<sub>1..u</sub>, m<sub>1..u</sub>, sig<sub>1..u</s
 ** Let ''P<sub>i</sub> = lift_x_even_y(int(pk<sub>i</sub>))''; fail if it fails.
 ** Let ''r<sub>i</sub> = int(sig<sub>i</sub>[0:32])''; fail if ''r<sub>i</sub> &ge; p''.
 ** Let ''s<sub>i</sub> = int(sig<sub>i</sub>[32:64])''; fail if ''s<sub>i</sub> &ge; n''.
-** Let ''e<sub>i</sub> = int(hash<sub>BIP340/challenge</sub>(bytes(r<sub>i</sub>) || bytes(P<sub>i</sub>) || m<sub>i</sub>)) mod n''.
+** Let ''e<sub>i</sub> = int(hash<sub>BIP0340/challenge</sub>(bytes(r<sub>i</sub>) || bytes(P<sub>i</sub>) || m<sub>i</sub>)) mod n''.
 ** Let ''R<sub>i</sub> = lift_x_even_y(r<sub>i</sub>)''; fail if ''lift_x_even_y(r<sub>i</sub>)'' fails.
 * Fail if ''(s<sub>1</sub> + a<sub>2</sub>s<sub>2</sub> + ... + a<sub>u</sub>s<sub>u</sub>)⋅G &ne; R<sub>1</sub> + a<sub>2</sub>⋅R<sub>2</sub> + ... + a<sub>u</sub>⋅R<sub>u</sub> + e<sub>1</sub>⋅P<sub>1</sub> + (a<sub>2</sub>e<sub>2</sub>)⋅P<sub>2</sub> + ... + (a<sub>u</sub>e<sub>u</sub>)⋅P<sub>u</sub>''.
 * Return success iff no failure occurred before reaching this point.