wallet: bugfix, 'CoinsResult::Erase' is erasing only one output of the set

The loop break shouldn't have being there.

Author: furszy

src/wallet/spend.cpp

@@ -102,15 +102,13 @@ void CoinsResult::Clear() {
     coins.clear();
 }
 
-void CoinsResult::Erase(std::set<COutPoint>& preset_coins)
+void CoinsResult::Erase(const std::unordered_set<COutPoint, SaltedOutpointHasher>& coins_to_remove)
 {
-    for (auto& it : coins) {
-        auto& vec = it.second;
-        auto i = std::find_if(vec.begin(), vec.end(), [&](const COutput &c) { return preset_coins.count(c.outpoint);});
-        if (i != vec.end()) {
-            vec.erase(i);
-            break;
-        }
+    for (auto& [type, vec] : coins) {
+        auto remove_it = std::remove_if(vec.begin(), vec.end(), [&](const COutput& coin) {
+            return coins_to_remove.count(coin.outpoint) == 1;
+        });
+        vec.erase(remove_it, vec.end());
     }
 }
 

src/wallet/spend.h

@@ -47,7 +47,7 @@ struct CoinsResult {
      * i.e., methods can work with individual OutputType vectors or on the entire object */
     size_t Size() const;
     void Clear();
-    void Erase(std::set<COutPoint>& preset_coins);
+    void Erase(const std::unordered_set<COutPoint, SaltedOutpointHasher>& coins_to_remove);
     void Shuffle(FastRandomContext& rng_fast);
     void Add(OutputType type, const COutput& out);