Show all files which contain a link to the current file in a list

[strumgeistxu]

I have a series of files (*.md) with the following structure:

1. Summary files A1, B1, C1, ...
2. Files a1, a2, b1, b2, c1, c2, ...
   In the 2nd file series, a1 and a2 contains a link [[A1]], b1 and b2 contains a link [[B1]], c1 and c2 contains a link [[C1]], and so on.
   What I want:
3. To show a1 and a2 as a list in A1, b1 and b2 as a list in B1, c1 and c2 as a list in C1, ...
4. Put the code block into a template file which requires the minimum change.
   I'm aware that I can do this (for A1, for example) by:

list
from %folder and [[A1]]
where %conditions

To fulfill my 2nd wish, I want to replace the link [[A1]] in the code block with a link with directs to the name of the current file.
I tried to replace [[A1]] with this.file.name or this.file.link, but it didn't work.
Appreciate if anyone has an idea. Thanks!

[strumgeistxu]

Alright, find the answer by myself. Not sure if it's the solid answer but worked for me.

list
from %folder and [[]]
where %conditions

This will do the thing. Simply leave the link empty.