Filter out task tree with tag and completed recursively.

[oliveagle]

given the following task tree, how to filter out only task branch with #WIP tag ?

• x0-0
  • x1-0
    • x2-0
      • x3-0 #WIP
      • x3-1
    • x2-1
      • x3-2 #WIP
      • X3-3
  • x1-1
  • x1-2
    • x2-2
    • x2-3
• x0-1

this is what I want:

• x0-0
  • x1-0
    • x2-0
      • x3-0 #WIP

this is what I come up with. which is not correct

const pagesOkr = dv.pages('"Tasks"').file.tasks

// recersive filter 
const filterSubtasksWip = (t) => ({
  ...t, 
  subtasks: t.subtasks.values.map(filterSubtasksWip).filter(
		st => !st.completed
	)
})

pagesOkr.values = pagesOkr.values.map(filterSubtasksWip)


// filter 1 level task
pagesOkr.values = pagesOkr.values.filter(
	t => !t.completed && (
		t.text.toUpperCase().contains("#WIP") || t.subtasks.length > 0
	)
)

dv.taskList(pagesOkr)

[oliveagle]

this works

// const pagesOkr = dv.pages('"Tasks"').file.tasks
const pagesOkr = dv.pages().file.tasks


const filterCompletedSubTasks = (t) => ({
  ...t,
  subtasks: t.subtasks.values.filter(
	  	st => !st.completed
  	)
	.map(filterCompletedSubTasks)
})

pagesOkr.values = pagesOkr.values.map(filterCompletedSubTasks)
pagesOkr.values = pagesOkr.values.filter(t=> !t.completed)


function filterWIP(t) {
		if (t.completed) return;

		if ( !t.subtasks || t.subtasks.length <= 0) {
			if ( t.text.contains("#WIP") ){
				return t;
			}
			return;
		}

		let subs = t.subtasks.map(filterWIP).filter(st => st)
		t.subtasks = subs
		if (subs.length > 0){
			return t;
		} else {
			if (t.text.contains("#WIP")) {
				return t;
			}
			return;
		}
}

pagesOkr.values = pagesOkr.values.map(filterWIP).filter(t => t && (
		t.subtasks.length > 0 || t.text.contains("#WIP")
	)
)

dv.taskList(pagesOkr)