diff --git a/README.md b/README.md
index 2990f94..5c75d52 100644
--- a/README.md
+++ b/README.md
@@ -35,22 +35,47 @@ Answer the following data queries. Keep track of the SQL you write by pasting it
 
 ### find all customers that live in London. Returns 6 records.
 > This can be done with SELECT and WHERE clauses
+```
+select contact_title, contact_name, country, city
+from customers
+where city = 'London'
+```
 
 
 ### find all customers with postal code 1010. Returns 3 customers.
 > This can be done with SELECT and WHERE clauses
+```
+select contact_title, contact_name, country, city
+from customers
+where postal_code = '1010'
+```
 
 
 ### find the phone number for the supplier with the id 11. Should be (010) 9984510.
 > This can be done with SELECT and WHERE clauses
 
+```
+select company_name, phone
+from suppliers
+where supplier_id = '11'
+```
 
 ### list orders descending by the order date. The order with date 1998-05-06 should be at the top.
 > This can be done with SELECT, WHERE, and ORDER BY clauses
+```
+select customer_id, ship_name, order_date
+from orders
+order by order_date desc
+```
 
 
 ### find all suppliers who have names longer than 20 characters. You can use `length(company_name)` to get the length of the name. Returns 11 records.
 > This can be done with SELECT and WHERE clauses
+```
+select supplier_id, company_name, city
+from suppliers
+where length(company_name) > 20
+```
 
 
 ### find all customers that include the word 'MARKET' in the contact title. Should return 19 records.
@@ -59,7 +84,11 @@ Answer the following data queries. Keep track of the SQL you write by pasting it
 > Don't forget the wildcard '%' symbols at the beginning and end of your substring to denote it can appear anywhere in the string in question
 
 > Remember to convert your contact title to all upper case for case insenstive comparing so upper(contact_title)
-
+```
+select *
+from customers
+where upper(contact_title) like '%MARKET%'
+```
 
 ### add a customer record for   
 * customer id is 'SHIRE'
@@ -70,25 +99,52 @@ Answer the following data queries. Keep track of the SQL you write by pasting it
 * the postal code is '111'
 * the country is 'Middle Earth'
 > This can be done with the INSERT INTO clause
+```
+insert into customers(customer_id, company_name, contact_name, address, city, postal_code, country)
+values('SHIRE', 'The Shire', 'Bilbo Baggins', '1 Hobbit-Hole', 'Bag End', '111', 'Middle Earth')
 
+```
 
 ### update _Bilbo Baggins_ record so that the postal code changes to _"11122"_.
 > This can be done with UPDATE and WHERE clauses
-
+```
+update customers
+set postal_code = '11122'
+where customer_id = 'SHIRE'
+```
 
 ### list orders grouped by customer showing the number of orders per customer. _Rattlesnake Canyon Grocery_ should have 18 orders.
 > This can be done with SELECT, COUNT, JOIN and GROUP BY clauses. Your count should focus on a field in the Orders table, not the Customer table
 
 > There is more information about the COUNT clause on [W3 Schools](https://www.w3schools.com/sql/sql_count_avg_sum.asp)
-
+```
+select count(o.order_id), c.contact_name, c.company_name
+from orders o join customers c 
+on o.customer_id = c.customer_id
+group by c.contact_name, c.company_name
+order by count(o.order_id)
+```
 
 ### list customers names and the number of orders per customer. Sort the list by number of orders in descending order. _Save-a-lot Markets should be at the top with 31 orders followed by _Ernst Handle_ with 30 orders. Last should be _Centro comercial Moctezuma_ with 1 order.
 > This can be done by adding an ORDER BY clause to the previous answer
-
+```
+select count(o.order_id), c.contact_name, c.company_name
+from orders o join customers c 
+on o.customer_id = c.customer_id
+group by c.contact_name, c.company_name
+order by count(o.order_id) desc
+```
 
 ### list orders grouped by customer's city showing number of orders per city. Returns 69 Records with _Aachen_ showing 6 orders and _Albuquerque_ showing 18 orders.
 > This is very similar to the previous two queries, however, it focuses on the City rather than the CustomerName
 
+```
+select count(o.order_id), c.city
+from customers c join orders o
+on o.customer_id = c.customer_id
+group by c.city
+order by c.city
+```
 
 ## Data Normalization
 
@@ -102,6 +158,38 @@ Take the following data and normalize it into a 3NF database.
 | Bob         | Joe      | Horse    |            |            |            |            | No          | No           |
 | Sam         | Ginger   | Dog      | Miss Kitty | Cat        | Bubble     | Fish       | Yes         | No           |
 
+
+
+
+| Person Name |Fenced Yard | City Dweller | Person Id    |
+|-------------|------------|--------------|--------------|
+| Jane        |No          | Yes          | 1            |
+| Bob         |No          | No           | 2            |
+| Sam         |Yes         | No           | 3            |
+
+
+| Person Id   | Pet Id   | Pet Name | Pet Type   | 
+|-------------|----------|----------|------------|
+| 1           | 1        | Ellie    | Dog        |
+| 1           | 2        | Tiger    | Cat        |
+| 1           | 3        | Toby     | Turtle     |
+| 2           | 4        | Joe      |Horse       | 
+| 3           | 5        | Ginger   | Dog        |
+| 3           | 6        |Miss Kitty| Cat        |
+| 3           | 7        | Bubble   | Fish       |
+
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 ---
 ## Stretch Goals