Skip to content
Discussion options

You must be logged in to vote

So, it turns out I don't even need powercalc :-) I can just create an integral helper for my power sensor which ill do the exact same thing! So my use case is solved but I'm not sure if you want to investigate this any further.

Replies: 2 comments

Comment options

You must be logged in to vote
0 replies
Answer selected by gregtakacs
Comment options

You must be logged in to vote
0 replies
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
2 participants