118.PasclesTringle.java

Given an integer numRows, return the first numRows of Pascal's triangle.

In Pascal's triangle, each number is the sum of the two numbers directly above it as shown:


 

Example 1:

Input: numRows = 5
Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]
Example 2:

Input: numRows = 1
Output: [[1]]
 

Constraints:

1 <= numRows <= 30
class Solution {
    public List<List<Integer>> generate(int numRows) {
        List<List<Integer>> triangle = new ArrayList<List<Integer>>();

        triangle.add(new ArrayList<>());
        triangle.get(0).add(1);

        for (int rowNum = 1; rowNum < numRows; rowNum++) {
            List<Integer> row = new ArrayList<>();
            List<Integer> prevRow = triangle.get(rowNum - 1);

            // The first row element is always 1.
            row.add(1);

            // Each triangle element (other than the first and last of each row)
            // is equal to the sum of the elements above-and-to-the-left and
            // above-and-to-the-right.
            for (int j = 1; j < rowNum; j++) {
                row.add(prevRow.get(j - 1) + prevRow.get(j));
            }

            // The last row element is always 1.
            row.add(1);

            triangle.add(row);
        }

        return triangle;
    }
}