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209. Minimum Size Subarray Sum.java
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58 lines (44 loc) · 1.39 KB
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209. Minimum Size Subarray Sum
Solved
Medium
Topics
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Given an array of positive integers nums and a positive integer target, return the minimal length of a subarray whose sum is greater than or equal to target. If there is no such subarray, return 0 instead.
Example 1:
Input: target = 7, nums = [2,3,1,2,4,3]
Output: 2
Explanation: The subarray [4,3] has the minimal length under the problem constraint.
Example 2:
Input: target = 4, nums = [1,4,4]
Output: 1
Example 3:
Input: target = 11, nums = [1,1,1,1,1,1,1,1]
Output: 0
Constraints:
1 <= target <= 109
1 <= nums.length <= 105
1 <= nums[i] <= 104
Follow up: If you have figured out the O(n) solution, try coding another solution of which the time complexity is O(n log(n)).class Solution {
public int minSubArrayLen(int target, int[] nums) {
int i = 0;
int minLength = Integer.MAX_VALUE;
int currentSum = 0;
for (int j = 0; j < nums.length; j++) {
currentSum += nums[j];
while (currentSum >= target) {
if ((j - i + 1) < minLength) {
minLength = j - i + 1;
} else {
currentSum -= nums[i];
i++;
}
}
}
if (minLength != Integer.MAX_VALUE) {
return minLength;
} else {
return 0;
}
}
}