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57_InsertInterval.py
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56 lines (40 loc) · 1.55 KB
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# coding: utf8
"""
题目链接: https://leetcode.com/problems/insert-interval/description.
题目描述:
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).
You may assume that the intervals were initially sorted according to their start times.
Example 1:
Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].
Example 2:
Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].
This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].
"""
# Definition for an interval.
class Interval(object):
def __init__(self, s=0, e=0):
self.start = s
self.end = e
def __repr__(self):
return '(start: {0}, end: {1})'.format(self.start, self.end)
class Solution(object):
def insert(self, intervals, newInterval):
"""
:type intervals: List[Interval]
:type newInterval: Interval
:rtype: List[Interval]
"""
intervals.append(newInterval)
result = []
intervals.sort(key=lambda val: val.start)
first_interval = intervals[0]
start, end = first_interval.start, first_interval.end
for interval in intervals:
if interval.start <= end:
end = max(end, interval.end)
else:
result.append(Interval(start, end))
start = interval.start
end = interval.end
result.append(Interval(start, end))
return result