feat: Query shows all 5 guest by corresponding records in the checked out items table

Author: brooklynharden

lesson_25/db/db_app/src/main/resources/queries/brooklynharden/brooklynharden.sql

@@ -13,3 +13,10 @@ INNER JOIN media_items ON checked_out_items.item_id = media_items.id
 GROUP BY 
 guests.name;
 
+
+SELECT guests.name, checked_out_items.*
+FROM guests
+LEFT JOIN checked_out_items ON guests.email = checked_out_items.email
+GROUP BY guests.name;
+
+