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Words Containing Character
Raymond Chen edited this page Aug 1, 2024
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TIP102 Unit 1 Session 1 Advanced (Click for link to problem statements)
- 💡 Difficulty: Easy
- ⏰ Time to complete: 10 mins
- 🛠️ Topics: Arrays, Strings, Iteration
Understand what the interviewer is asking for by using test cases and questions about the problem.
- Established a set (2-3) of test cases to verify their own solution later.
- Established a set (1-2) of edge cases to verify their solution handles complexities.
- Have fully understood the problem and have no clarifying questions.
- Have you verified any Time/Space Constraints for this problem?
- The function
words_with_char()
should take a list of strings words and a character x, and return a list of indices representing the words that contain the character x.
HAPPY CASE
Input: words = [""batman"", ""superman""], x = ""a""
Expected Output: [0, 1]
Input: words = [""black panther"", ""hulk"", ""black widow"", ""thor""], x = ""a""
Expected Output: [0, 2]
EDGE CASE
Input: words = [""star-lord"", ""gamora"", ""groot"", ""rocket""], x = ""z""
Expected Output: []
Input: words = ["""", ""superman"", """"], x = ""a""
Expected Output: [1]
Input: words = ["""", """", """"], x = ""a""
Expected Output: []
Plan the solution with appropriate visualizations and pseudocode.
General Idea: Iterate through the list of words and check if the character x is present in each word. If it is, append the index of that word to the result list.
1. Initialize an empty list `indices` to store the result.
2. Iterate through the list `words` using an index `i`.
a. If the character `x` is in the word at index `i`, append `i` to `indices`.
3. Return `indices`.
- Forgetting to handle cases where the list words is empty.
- Incorrectly checking if the character x is in the word.
Implement the code to solve the algorithm.
def words_with_char(words, x):
indices = []
for i in range(len(words)):
if x in words[i]:
indices.append(i)
return indices