[dcl.fct.def.default] Clarify that the rule concerning how the type of a

defaulted function can differ from the type of an implicitly-declared
function only applies to the functions that are implicitly declared.

Author: zygoloid

source/declarations.tex

@@ -6067,9 +6067,8 @@
 \item not have default arguments.
 \end{itemize}
 
-% FIXME: there's no such thing as an implicit declaration of a comparison operator
 \pnum
-The type \tcode{T}$_1$ of an explicitly defaulted function \tcode{F}
+The type \tcode{T}$_1$ of an explicitly defaulted special member function \tcode{F}
 is allowed to differ from the type \tcode{T}$_2$ it would have had
 if it were implicitly declared, as follows:
 \begin{itemize}