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314 | 314 | #include <string>
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315 | 315 |
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316 | 316 | struct C {
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317 |
| - std::string s; // \tcode{std::string} is the standard library class\iref{string.classes} |
| 317 | + std::string s; // \tcode{std::string} is the standard library class\iref{string.classes} |
318 | 318 | };
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319 | 319 |
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320 | 320 | int main() {
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2616 | 2616 |
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2617 | 2617 | void h()
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2618 | 2618 | {
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2619 |
| - AB::g(); // \tcode{g} is declared directly in \tcode{AB}, therefore \tcode{S} is $\{ \tcode{AB::g()} \}$ and \tcode{AB::g()} is chosen |
| 2619 | + AB::g(); // \tcode{g} is declared directly in \tcode{AB}, therefore \tcode{S} is $\{ \tcode{AB::g()} \}$ and \tcode{AB::g()} is chosen |
2620 | 2620 |
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2621 |
| - AB::f(1); // \tcode{f} is not declared directly in \tcode{AB} so the rules are applied recursively to \tcode{A} and \tcode{B}; |
2622 |
| - // namespace \tcode{Y} is not searched and \tcode{Y::f(float)} is not considered; |
2623 |
| - // \tcode{S} is $\{ \tcode{A::f(int)}, \tcode{B::f(char)} \}$ and overload resolution chooses \tcode{A::f(int)} |
| 2621 | + AB::f(1); // \tcode{f} is not declared directly in \tcode{AB} so the rules are applied recursively to \tcode{A} and \tcode{B}; |
| 2622 | + // namespace \tcode{Y} is not searched and \tcode{Y::f(float)} is not considered; |
| 2623 | + // \tcode{S} is $\{ \tcode{A::f(int)}, \tcode{B::f(char)} \}$ and overload resolution chooses \tcode{A::f(int)} |
2624 | 2624 |
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2625 |
| - AB::f('c'); // as above but resolution chooses \tcode{B::f(char)} |
| 2625 | + AB::f('c'); // as above but resolution chooses \tcode{B::f(char)} |
2626 | 2626 |
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2627 |
| - AB::x++; // \tcode{x} is not declared directly in \tcode{AB}, and is not declared in \tcode{A} or \tcode{B}, so the rules |
2628 |
| - // are applied recursively to \tcode{Y} and \tcode{Z}, \tcode{S} is $\{ \}$ so the program is ill-formed |
| 2627 | + AB::x++; // \tcode{x} is not declared directly in \tcode{AB}, and is not declared in \tcode{A} or \tcode{B}, so the rules |
| 2628 | + // are applied recursively to \tcode{Y} and \tcode{Z}, \tcode{S} is $\{ \}$ so the program is ill-formed |
2629 | 2629 |
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2630 |
| - AB::i++; // \tcode{i} is not declared directly in \tcode{AB} so the rules are applied recursively to \tcode{A} and \tcode{B}, |
2631 |
| - // \tcode{S} is $\{ \tcode{A::i}, \tcode{B::i} \}$ so the use is ambiguous and the program is ill-formed |
| 2630 | + AB::i++; // \tcode{i} is not declared directly in \tcode{AB} so the rules are applied recursively to \tcode{A} and \tcode{B}, |
| 2631 | + // \tcode{S} is $\{ \tcode{A::i}, \tcode{B::i} \}$ so the use is ambiguous and the program is ill-formed |
2632 | 2632 |
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2633 |
| - AB::h(16.8); // \tcode{h} is not declared directly in \tcode{AB} and not declared directly in \tcode{A} or \tcode{B} so the rules |
2634 |
| - // are applied recursively to \tcode{Y} and \tcode{Z}, \tcode{S} is $\{ \tcode{Y::h(int)}, \tcode{Z::h(double)} \}$ and |
2635 |
| - // overload resolution chooses \tcode{Z::h(double)} |
| 2633 | + AB::h(16.8); // \tcode{h} is not declared directly in \tcode{AB} and not declared directly in \tcode{A} or \tcode{B} so the rules |
| 2634 | + // are applied recursively to \tcode{Y} and \tcode{Z}, \tcode{S} is $\{ \tcode{Y::h(int)}, \tcode{Z::h(double)} \}$ and |
| 2635 | + // overload resolution chooses \tcode{Z::h(double)} |
2636 | 2636 | }
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2637 | 2637 | \end{codeblock}
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2638 | 2638 | \end{example}
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