[alg.move] Make "E(n)" explicitly depend on "n"

Author: tkoeppe

source/algorithms.tex

@@ -6685,7 +6685,7 @@
 
 \begin{itemdescr}
 \pnum
-Let $E$ be
+Let $E(n)$ be
 \begin{itemize}
 \item
   \tcode{std::move(*(first + $n$))}
@@ -6705,7 +6705,7 @@
 Moves elements in the range \range{first}{last}
 into the range \range{result}{result + $N$}
 starting from \tcode{first} and proceeding to \tcode{last}.
-For each non-negative integer $n < N$, performs \tcode{*(result + $n$) = $E$}.
+For each non-negative integer $n < N$, performs \tcode{*(result + $n$) = $E(n)$}.
 
 \pnum
 \returns
@@ -6743,13 +6743,9 @@
 
 \begin{itemdescr}
 \pnum
-Let $E$ be:
+Let $E(n)$ be:
 \begin{itemize}
 \item
-  %FIXME: This is extremely confusing to read from top to bottom
-  %       because $n$ is defined multiple paragraphs below.
-  %       Can we make this $E(\tcode{i})$ or something?
-  %       We did that for copy_if.
   \tcode{std::move(*(first + $n$))}
   for the overload in namespace \tcode{std};
 \item
@@ -6774,7 +6770,7 @@
 Moves elements in the range \range{first}{first + $N$}
 into the range \range{result}{result + $N$}.
 For each non-negative integer $n < N$,
-performs \tcode{*(result + $n$) = $E$}.
+performs \tcode{*(result + $n$) = $E(n)$}.
 
 \pnum
 \returns
@@ -6811,7 +6807,7 @@
 
 \begin{itemdescr}
 \pnum
-Let $E$ be
+Let $E(n)$ be
 \begin{itemize}
 \item
   \tcode{std::move(*(last - $n$))}
@@ -6836,7 +6832,7 @@
 when \tcode{last} is in the range \range{result - $N$}{result}.
 \end{footnote}
 For each positive integer $n \le N$,
-performs \tcode{*(result - $n$) = $E$}.
+performs \tcode{*(result - $n$) = $E(n)$}.
 
 \pnum
 \returns