-
Notifications
You must be signed in to change notification settings - Fork 1
Expand file tree
/
Copy pathleft_and_right_sum_deference.cpp
More file actions
50 lines (43 loc) · 1.33 KB
/
left_and_right_sum_deference.cpp
File metadata and controls
50 lines (43 loc) · 1.33 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
//program for make left and light sum array by prefix-sum array
//problem link: https://leetcode.com/problems/left-and-right-sum-differences/
/*
process: creaate 2 prefix sum array
1 st prefix sum array work first - (last -1)
2 nd prefix sum array work last to 1 index
than find out absoulate deference betwenn them and take another array name answer.
*/
class Solution {
public:
vector<int> leftRightDifference(vector<int>& nums) {
vector<int>preSum1,preSum2,ans;
//handling corner case
if(nums.size() == 0) return ans;
else if(nums.size() == 1)
{
ans.push_back(0);
return ans;
}
preSum1.push_back(0);
preSum2.push_back(0);
preSum1.push_back(nums[0]);
preSum2.push_back(nums[nums.size() -1]);//last value of nums array
//now make prefix-sum1 array
for(int i = 1; i < nums.size() -1; i++)
{
preSum1.push_back(nums[i] + preSum1.back());
}
//now make prefix-sum2 array
for(int i = nums.size() -2; i > 0; i--)
{
preSum2.push_back(nums[i] + preSum2.back());
}
//now make ansewer vector
int j = nums.size() -1;
for(int i = 0; i< nums.size(); i++)
{
ans.push_back(abs(preSum1[i] - preSum2[j]));
j--;
}
return ans;
}
};