Update Variant documentation comment about class_name

Author: fkeyzuwu

doc/classes/Variant.xml

@@ -42,8 +42,8 @@
 		        # Note that Objects are their own special category.
 		        # To get the name of the underlying Object type, you need the `get_class()` method.
 		        print("foo is a(n) %s" % foo.get_class()) # inject the class name into a formatted string.
-		        # Note also that there is not yet any way to get a script's `class_name` string easily.
-		        # To fetch that value, you can use ProjectSettings.get_global_class_list().
+		        # Note that this does not get the script's `class_name` global identifier.
+		        # If the `class_name` is needed, use `foo.get_script().get_global_name()` instead.
 		[/gdscript]
 		[csharp]
 		Variant foo = 2;