@@ -84849,7 +84849,7 @@ <h3 id="_3">方法一:贪心 + 二分查找</h3>
8484984849<p>我们定义函数 $check(T)$,表示是否存在一种分组方案,使得每一组去掉最大值后不超过 $T$,并且分组数不超过 $m$。</p>
8485084850<p>我们可以用贪心的方法来判断是否存在这样的分组方案。我们从左到右遍历题目,将题目耗时加入当前总耗时 $s$,并更新当前分组的最大值 $mx$。如果当前总耗时 $s$ 减去当前分组的最大值 $mx$ 大于 $T$,则将当前题目作为新的分组的第一题,更新 $s$ 和 $mx$。继续遍历题目,直到遍历完所有题目。如果分组数不超过 $m$,则说明存在这样的分组方案,返回 $true$,否则返回 $false$。</p>
8485184851<p>时间复杂度 $O(n \times \log S)$,空间复杂度 $O(1)$。其中 $n$ 和 $S$ 分别为题目数量和题目总耗时。</p>
84852- <div class="tabbed-set tabbed-alternate" data-tabs="1:5 "><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><input id="__tabbed_1_3" name="__tabbed_1" type="radio" /><input id="__tabbed_1_4" name="__tabbed_1" type="radio" /><input id="__tabbed_1_5" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">Python3</label><label for="__tabbed_1_2">Java</label><label for="__tabbed_1_3">C++</label><label for="__tabbed_1_4">Go</label><label for="__tabbed_1_5">TypeScript</label></div>
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8485384853<div class="tabbed-content">
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8485584855<div class="highlight"><table class="highlighttable"><tr><td class="linenos"><div class="linenodiv"><pre><span></span><span class="normal"> 1</span>
@@ -85111,6 +85111,74 @@ <h3 id="_3">方法一:贪心 + 二分查找</h3>
8511185111<span class="p">}</span>
8511285112</code></pre></div></td></tr></table></div>
8511385113</div>
85114+ <div class="tabbed-block">
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85148+ <span class="kd">func</span> <span class="nf">minTime</span><span class="p">(</span><span class="kc">_</span> <span class="n">time</span><span class="p">:</span> <span class="p">[</span><span class="nb">Int</span><span class="p">],</span> <span class="kc">_</span> <span class="n">m</span><span class="p">:</span> <span class="nb">Int</span><span class="p">)</span> <span class="p">-></span> <span class="nb">Int</span> <span class="p">{</span>
85149+ <span class="kd">var</span> <span class="nv">left</span> <span class="p">=</span> <span class="mi">0</span>
85150+ <span class="kd">var</span> <span class="nv">right</span> <span class="p">=</span> <span class="n">time</span><span class="p">.</span><span class="bp">reduce</span><span class="p">(</span><span class="mi">0</span><span class="p">,</span> <span class="o">+</span><span class="p">)</span>
85151+
85152+ <span class="k">while</span> <span class="kr">left</span> <span class="o"><</span> <span class="kr">right</span> <span class="p">{</span>
85153+ <span class="kd">let</span> <span class="nv">mid</span> <span class="p">=</span> <span class="p">(</span><span class="kr">left</span> <span class="o">+</span> <span class="kr">right</span><span class="p">)</span> <span class="o">/</span> <span class="mi">2</span>
85154+ <span class="k">if</span> <span class="n">check</span><span class="p">(</span><span class="n">mid</span><span class="p">,</span> <span class="n">time</span><span class="p">,</span> <span class="n">m</span><span class="p">)</span> <span class="p">{</span>
85155+ <span class="kr">right</span> <span class="p">=</span> <span class="n">mid</span>
85156+ <span class="p">}</span> <span class="k">else</span> <span class="p">{</span>
85157+ <span class="kr">left</span> <span class="p">=</span> <span class="n">mid</span> <span class="o">+</span> <span class="mi">1</span>
85158+ <span class="p">}</span>
85159+ <span class="p">}</span>
85160+ <span class="k">return</span> <span class="kr">left</span>
85161+ <span class="p">}</span>
85162+
85163+ <span class="kd">private</span> <span class="kd">func</span> <span class="nf">check</span><span class="p">(</span><span class="kc">_</span> <span class="n">t</span><span class="p">:</span> <span class="nb">Int</span><span class="p">,</span> <span class="kc">_</span> <span class="n">time</span><span class="p">:</span> <span class="p">[</span><span class="nb">Int</span><span class="p">],</span> <span class="kc">_</span> <span class="n">m</span><span class="p">:</span> <span class="nb">Int</span><span class="p">)</span> <span class="p">-></span> <span class="nb">Bool</span> <span class="p">{</span>
85164+ <span class="kd">var</span> <span class="nv">sum</span> <span class="p">=</span> <span class="mi">0</span>
85165+ <span class="kd">var</span> <span class="nv">maxTime</span> <span class="p">=</span> <span class="mi">0</span>
85166+ <span class="kd">var</span> <span class="nv">days</span> <span class="p">=</span> <span class="mi">1</span>
85167+
85168+ <span class="k">for</span> <span class="n">x</span> <span class="k">in</span> <span class="n">time</span> <span class="p">{</span>
85169+ <span class="n">sum</span> <span class="o">+=</span> <span class="n">x</span>
85170+ <span class="n">maxTime</span> <span class="p">=</span> <span class="bp">max</span><span class="p">(</span><span class="n">maxTime</span><span class="p">,</span> <span class="n">x</span><span class="p">)</span>
85171+ <span class="k">if</span> <span class="n">sum</span> <span class="o">-</span> <span class="n">maxTime</span> <span class="o">></span> <span class="n">t</span> <span class="p">{</span>
85172+ <span class="n">sum</span> <span class="p">=</span> <span class="n">x</span>
85173+ <span class="n">maxTime</span> <span class="p">=</span> <span class="n">x</span>
85174+ <span class="n">days</span> <span class="o">+=</span> <span class="mi">1</span>
85175+ <span class="p">}</span>
85176+ <span class="p">}</span>
85177+ <span class="k">return</span> <span class="n">days</span> <span class="o"><=</span> <span class="n">m</span>
85178+ <span class="p">}</span>
85179+ <span class="p">}</span>
85180+ </code></pre></div></td></tr></table></div>
85181+ </div>
8511485182</div>
8511585183</div>
8511685184<!-- solution:end -->
@@ -85144,6 +85212,11 @@ <h3 id="_3">方法一:贪心 + 二分查找</h3>
8514485212
8514585213 <nav>
8514685214
85215+ <a href="https://github.com/klever34" class="md-author" title="@klever34">
85216+
85217+ <img src="https://avatars.githubusercontent.com/u/12745225?v=4&size=72" alt="klever34">
85218+ </a>
85219+
8514785220 <a href="https://github.com/yanglbme" class="md-author" title="@yanglbme">
8514885221
8514985222 <img src="https://avatars.githubusercontent.com/u/21008209?v=4&size=72" alt="yanglbme">
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