Update Solution.java

3 Error's resolved

Author: CodersAcademy006

solution/1300-1399/1330.Reverse Subarray To Maximize Array Value/Solution.java

@@ -1,30 +1,31 @@
 class Solution {
-    public int maxValueAfterReverse(int[] nums) {
-        int n = nums.length;
-        int s = 0;
-        for (int i = 0; i < n - 1; ++i) {
-            s += Math.abs(nums[i] - nums[i + 1]);
-        }
-        int ans = s;
-        for (int i = 0; i < n - 1; ++i) {
-            ans = Math.max(
-                ans, s + Math.abs(nums[0] - nums[i + 1]) - Math.abs(nums[i] - nums[i + 1]));
-            ans = Math.max(
-                ans, s + Math.abs(nums[n - 1] - nums[i]) - Math.abs(nums[i] - nums[i + 1]));
-        }
-        int[] dirs = {1, -1, -1, 1, 1};
-        final int inf = 1 << 30;
-        for (int k = 0; k < 4; ++k) {
-            int k1 = dirs[k], k2 = dirs[k + 1];
-            int mx = -inf, mi = inf;
-            for (int i = 0; i < n - 1; ++i) {
-                int a = k1 * nums[i] + k2 * nums[i + 1];
-                int b = Math.abs(nums[i] - nums[i + 1]);
-                mx = Math.max(mx, a - b);
-                mi = Math.min(mi, a + b);
-            }
-            ans = Math.max(ans, s + Math.max(0, mx - mi));
-        }
-        return ans;
+
+  public int maxValueAfterReverse(int[] nums) {
+    int n = nums.length;
+    int s = 0;
+    for (int i = 0; i < n - 1; ++i) {
+      s += Math.abs(nums[i] - nums[i + 1]);
     }
-}
+    int ans = s;
+    for (int i = 0; i < n - 1; ++i) {
+      ans = Math.max(
+          ans, s + Math.abs(nums[0] - nums[i + 1]) - Math.abs(nums[i] - nums[i + 1]));
+      ans = Math.max(
+          ans, s + Math.abs(nums[n - 1] - nums[i]) - Math.abs(nums[i] - nums[i + 1]));
+    }
+    int[] dirs = {1, -1, -1, 1, 1};
+    final int inf = 1 << 30;
+    for (int k = 0; k < 4; ++k) {
+      int k1 = dirs[k], k2 = dirs[k + 1];
+      int mx = -inf, mi = inf;
+      for (int i = 0; i < n - 1; ++i) {
+        int a = k1 * nums[i] + k2 * nums[i + 1];
+        int b = Math.abs(nums[i] - nums[i + 1]);
+        mx = Math.max(mx, a - b);
+        mi = Math.min(mi, a + b);
+      }
+      ans = Math.max(ans, s + Math.max(0, mx - mi));
+    }
+    return ans;
+  }
+}