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feat: update lc problems (#3686)
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‎solution/0700-0799/0729.My Calendar I/README_EN.md‎

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<p>A <strong>double booking</strong> happens when two events have some non-empty intersection (i.e., some moment is common to both events.).</p>
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<p>The event can be represented as a pair of integers <code>start</code> and <code>end</code> that represents a booking on the half-open interval <code>[start, end)</code>, the range of real numbers <code>x</code> such that <code>start &lt;= x &lt; end</code>.</p>
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<p>The event can be represented as a pair of integers <code>startTime</code> and <code>endTime</code> that represents a booking on the half-open interval <code>[startTime, endTime)</code>, the range of real numbers <code>x</code> such that <code>startTime &lt;= x &lt; endTime</code>.</p>
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<p>Implement the <code>MyCalendar</code> class:</p>
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<ul>
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<li><code>MyCalendar()</code> Initializes the calendar object.</li>
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<li><code>boolean book(int start, int end)</code> Returns <code>true</code> if the event can be added to the calendar successfully without causing a <strong>double booking</strong>. Otherwise, return <code>false</code> and do not add the event to the calendar.</li>
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<li><code>boolean book(int startTime, int endTime)</code> Returns <code>true</code> if the event can be added to the calendar successfully without causing a <strong>double booking</strong>. Otherwise, return <code>false</code> and do not add the event to the calendar.</li>
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</ul>
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<p>&nbsp;</p>

‎solution/0700-0799/0731.My Calendar II/README_EN.md‎

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<p>A <strong>triple booking</strong> happens when three events have some non-empty intersection (i.e., some moment is common to all the three events.).</p>
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<p>The event can be represented as a pair of integers <code>start</code> and <code>end</code> that represents a booking on the half-open interval <code>[start, end)</code>, the range of real numbers <code>x</code> such that <code>start &lt;= x &lt; end</code>.</p>
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<p>The event can be represented as a pair of integers <code>startTime</code> and <code>endTime</code> that represents a booking on the half-open interval <code>[startTime, endTime)</code>, the range of real numbers <code>x</code> such that <code>startTime &lt;= x &lt; endTime</code>.</p>
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<p>Implement the <code>MyCalendarTwo</code> class:</p>
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<ul>
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<li><code>MyCalendarTwo()</code> Initializes the calendar object.</li>
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<li><code>boolean book(int start, int end)</code> Returns <code>true</code> if the event can be added to the calendar successfully without causing a <strong>triple booking</strong>. Otherwise, return <code>false</code> and do not add the event to the calendar.</li>
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<li><code>boolean book(int startTime, int endTime)</code> Returns <code>true</code> if the event can be added to the calendar successfully without causing a <strong>triple booking</strong>. Otherwise, return <code>false</code> and do not add the event to the calendar.</li>
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</ul>
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<p>&nbsp;</p>

‎solution/3300-3399/3330.Find the Original Typed String I/README.md‎

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comments: true
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difficulty: 简单
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3330.Find%20the%20Original%20Typed%20String%20I/README.md
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tags:
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- 字符串
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---
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‎solution/3300-3399/3330.Find the Original Typed String I/README_EN.md‎

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comments: true
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difficulty: Easy
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3330.Find%20the%20Original%20Typed%20String%20I/README_EN.md
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tags:
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- String
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‎solution/3300-3399/3331.Find Subtree Sizes After Changes/README.md‎

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3331.Find%20Subtree%20Sizes%20After%20Changes/README.md
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tags:
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- 树
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- 深度优先搜索
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- 数组
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- 哈希表
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- 字符串
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---
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‎solution/3300-3399/3331.Find Subtree Sizes After Changes/README_EN.md‎

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3331.Find%20Subtree%20Sizes%20After%20Changes/README_EN.md
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tags:
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- Tree
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- Depth-First Search
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- Array
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- Hash Table
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- String
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<li>Otherwise, <strong>remove</strong> the edge between <code>x</code> and its current parent and make node <code>y</code> the new parent of <code>x</code> by adding an edge between them.</li>
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</ul>
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<p>Return an array <code>answer</code> of size <code>n</code> where <code>answer[i]</code> is the <strong>size</strong> of the subtree rooted at node <code>i</code> in the <strong>final</strong> tree.</p>
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<p>A <strong>subtree</strong> of <code>treeName</code> is a tree consisting of a node in <code>treeName</code> and all of its descendants.</p>
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<p>Return an array <code>answer</code> of size <code>n</code> where <code>answer[i]</code> is the <strong>size</strong> of the <span data-keyword="subtree">subtree</span> rooted at node <code>i</code> in the <strong>final</strong> tree.</p>
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<p>&nbsp;</p>
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<p><strong class="example">Example 1:</strong></p>

‎solution/3300-3399/3332.Maximum Points Tourist Can Earn/README.md‎

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comments: true
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difficulty: 中等
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3332.Maximum%20Points%20Tourist%20Can%20Earn/README.md
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tags:
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- 数组
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- 动态规划
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- 矩阵
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‎solution/3300-3399/3332.Maximum Points Tourist Can Earn/README_EN.md‎

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comments: true
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difficulty: Medium
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3332.Maximum%20Points%20Tourist%20Can%20Earn/README_EN.md
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tags:
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- Array
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- Dynamic Programming
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- Matrix
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‎solution/3300-3399/3333.Find the Original Typed String II/README.md‎

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comments: true
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difficulty: 困难
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3333.Find%20the%20Original%20Typed%20String%20II/README.md
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tags:
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- 字符串
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- 动态规划
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- 前缀和
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‎solution/3300-3399/3333.Find the Original Typed String II/README_EN.md‎

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comments: true
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difficulty: Hard
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edit_url: https://github.com/doocs/leetcode/edit/main/solution/3300-3399/3333.Find%20the%20Original%20Typed%20String%20II/README_EN.md
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tags:
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- String
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- Dynamic Programming
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- Prefix Sum
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