deploy: 631791e

Author: acbin

en/lc/1884/index.html

@@ -79488,7 +79488,7 @@ <h2 id="solutions">Solutions</h2>
 
 <h3 id="solution-1-two-pointers-bitwise-operations">Solution 1: Two Pointers + Bitwise Operations</h3>
 <p>According to the problem description, we need to calculate the result of the bitwise OR operation of elements from index $l$ to $r$ in the array $\textit{nums}$, that is, $\textit{nums}[l] \lor \textit{nums}[l + 1] \lor \cdots \lor \textit{nums}[r]$, where $\lor$ represents the bitwise OR operation.</p>
-<p>If we fix the right endpoint $r$, then the range of the left endpoint $l$ is $[0, r]$. Each time we move the right endpoint $r$, the result of the bitwise OR operation will only increase. We use a variable $s$ to record the current result of the bitwise OR operation. If $s$ is greater than $k$, we move the left endpoint $l$ to the right until $s$ is less than or equal to $k$. During the process of moving the left endpoint $l$, we need to maintain an array $cnt$ to record the number of $0$s on each binary digit in the current interval. When $cnt[h] = 0$, it means that all elements in the current interval have a $1$ on the $h^{th}$ bit, and we can set the $h^{th}$ bit of $s$ to $0$.</p>
+<p>If we fix the right endpoint $r$, then the range of the left endpoint $l$ is $[0, r]$. Each time we move the right endpoint $r$, the result of the bitwise OR operation will only increase. We use a variable $s$ to record the current result of the bitwise OR operation. If $s$ is greater than $k$, we move the left endpoint $l$ to the right until $s$ is less than or equal to $k$. During the process of moving the left endpoint $l$, we need to maintain an array $cnt$ to record the number of $0$s on each binary digit in the current interval. When $cnt[h] = 0$, it means that all elements in the current interval have a $0$ on the $h^{th}$ bit, and we can set the $h^{th}$ bit of $s$ to $0$.</p>
 <p>The time complexity is $O(n \times \log M)$, and the space complexity is $O(\log M)$. Here, $n$ and $M$ respectively represent the length of the array $\textit{nums}$ and the maximum value in the array $\textit{nums}$.</p>
 <p>Similar Problems:</p>
 <ul>

en/lc/3171/index.html

@@ -79568,7 +79568,7 @@ <h2 id="solutions">Solutions</h2>
 <h3 id="solution-1-sorting">Solution 1: Sorting</h3>
 <p>First, we sort the array $\textit{nums}$. Then, we start taking elements from both ends of the array, calculating the sum of the two elements, and taking the minimum value. Finally, we return the minimum value divided by 2 as the answer.</p>
 <p>The time complexity is $O(n \log n)$, and the space complexity is $O(\log n)$, where $n$ is the length of the array $\textit{nums}$.</p>
-<div class="tabbed-set tabbed-alternate" data-tabs="1:5"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><input id="__tabbed_1_3" name="__tabbed_1" type="radio" /><input id="__tabbed_1_4" name="__tabbed_1" type="radio" /><input id="__tabbed_1_5" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">Python3</label><label for="__tabbed_1_2">Java</label><label for="__tabbed_1_3">C++</label><label for="__tabbed_1_4">Go</label><label for="__tabbed_1_5">TypeScript</label></div>
+<div class="tabbed-set tabbed-alternate" data-tabs="1:6"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><input id="__tabbed_1_3" name="__tabbed_1" type="radio" /><input id="__tabbed_1_4" name="__tabbed_1" type="radio" /><input id="__tabbed_1_5" name="__tabbed_1" type="radio" /><input id="__tabbed_1_6" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">Python3</label><label for="__tabbed_1_2">Java</label><label for="__tabbed_1_3">C++</label><label for="__tabbed_1_4">Go</label><label for="__tabbed_1_5">TypeScript</label><label for="__tabbed_1_6">Rust</label></div>
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 <div class="highlight"><table class="highlighttable"><tr><td class="linenos"><div class="linenodiv"><pre><span></span><span class="normal">1</span>
@@ -79579,7 +79579,7 @@ <h3 id="solution-1-sorting">Solution 1: Sorting</h3>
     <span class="k">def</span> <span class="nf">minimumAverage</span><span class="p">(</span><span class="bp">self</span><span class="p">,</span> <span class="n">nums</span><span class="p">:</span> <span class="n">List</span><span class="p">[</span><span class="nb">int</span><span class="p">])</span> <span class="o">-&gt;</span> <span class="nb">float</span><span class="p">:</span>
         <span class="n">nums</span><span class="o">.</span><span class="n">sort</span><span class="p">()</span>
         <span class="n">n</span> <span class="o">=</span> <span class="nb">len</span><span class="p">(</span><span class="n">nums</span><span class="p">)</span>
-        <span class="k">return</span> <span class="nb">min</span><span class="p">(</span><span class="n">nums</span><span class="p">[</span><span class="n">i</span><span class="p">]</span> <span class="o">+</span> <span class="n">nums</span><span class="p">[</span><span class="n">n</span> <span class="o">-</span> <span class="n">i</span> <span class="o">-</span> <span class="mi">1</span><span class="p">]</span> <span class="k">for</span> <span class="n">i</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="n">n</span> <span class="o">//</span> <span class="mi">2</span><span class="p">))</span> <span class="o">/</span> <span class="mi">2</span>
+        <span class="k">return</span> <span class="nb">min</span><span class="p">(</span><span class="n">nums</span><span class="p">[</span><span class="n">i</span><span class="p">]</span> <span class="o">+</span> <span class="n">nums</span><span class="p">[</span><span class="o">-</span><span class="n">i</span> <span class="o">-</span> <span class="mi">1</span><span class="p">]</span> <span class="k">for</span> <span class="n">i</span> <span class="ow">in</span> <span class="nb">range</span><span class="p">(</span><span class="n">n</span> <span class="o">//</span> <span class="mi">2</span><span class="p">))</span> <span class="o">/</span> <span class="mi">2</span>
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@@ -79670,6 +79670,24 @@ <h3 id="solution-1-sorting">Solution 1: Sorting</h3>
 <span class="p">}</span>
 </code></pre></div></td></tr></table></div>
 </div>
+<div class="tabbed-block">
+<div class="highlight"><table class="highlighttable"><tr><td class="linenos"><div class="linenodiv"><pre><span></span><span class="normal">1</span>
+<span class="normal">2</span>
+<span class="normal">3</span>
+<span class="normal">4</span>
+<span class="normal">5</span>
+<span class="normal">6</span>
+<span class="normal">7</span>
+<span class="normal">8</span></pre></div></td><td class="code"><div><pre><span></span><code><span class="k">impl</span><span class="w"> </span><span class="n">Solution</span><span class="w"> </span><span class="p">{</span>
+<span class="w">    </span><span class="k">pub</span><span class="w"> </span><span class="k">fn</span><span class="w"> </span><span class="nf">minimum_average</span><span class="p">(</span><span class="k">mut</span><span class="w"> </span><span class="n">nums</span><span class="p">:</span><span class="w"> </span><span class="nb">Vec</span><span class="o">&lt;</span><span class="kt">i32</span><span class="o">&gt;</span><span class="p">)</span><span class="w"> </span><span class="p">-&gt;</span><span class="w"> </span><span class="kt">f64</span><span class="w"> </span><span class="p">{</span>
+<span class="w">        </span><span class="n">nums</span><span class="p">.</span><span class="n">sort</span><span class="p">();</span>
+<span class="w">        </span><span class="kd">let</span><span class="w"> </span><span class="n">n</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="n">nums</span><span class="p">.</span><span class="n">len</span><span class="p">();</span>
+<span class="w">        </span><span class="kd">let</span><span class="w"> </span><span class="n">ans</span><span class="w"> </span><span class="o">=</span><span class="w"> </span><span class="p">(</span><span class="mi">0</span><span class="o">..</span><span class="n">n</span><span class="w"> </span><span class="o">/</span><span class="w"> </span><span class="mi">2</span><span class="p">).</span><span class="n">map</span><span class="p">(</span><span class="o">|</span><span class="n">i</span><span class="o">|</span><span class="w"> </span><span class="n">nums</span><span class="p">[</span><span class="n">i</span><span class="p">]</span><span class="w"> </span><span class="o">+</span><span class="w"> </span><span class="n">nums</span><span class="p">[</span><span class="n">n</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="n">i</span><span class="w"> </span><span class="o">-</span><span class="w"> </span><span class="mi">1</span><span class="p">]).</span><span class="n">min</span><span class="p">().</span><span class="n">unwrap</span><span class="p">();</span>
+<span class="w">        </span><span class="n">ans</span><span class="w"> </span><span class="k">as</span><span class="w"> </span><span class="kt">f64</span><span class="w"> </span><span class="o">/</span><span class="w"> </span><span class="mf">2.0</span>
+<span class="w">    </span><span class="p">}</span>
+<span class="p">}</span>
+</code></pre></div></td></tr></table></div>
+</div>
 </div>
 </div>
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