Added README.md file for Row With Maximum Ones

Author: achuatchaya

2737-row-with-maximum-ones/README.md

@@ -0,0 +1,40 @@
+<h2><a href="https://leetcode.com/problems/row-with-maximum-ones">Row With Maximum Ones</a></h2> <img src='https://img.shields.io/badge/Difficulty-Easy-brightgreen' alt='Difficulty: Easy' /><hr><p>Given a <code>m x n</code> binary matrix <code>mat</code>, find the <strong>0-indexed</strong> position of the row that contains the <strong>maximum</strong> count of <strong>ones,</strong> and the number of ones in that row.</p>
+
+<p>In case there are multiple rows that have the maximum count of ones, the row with the <strong>smallest row number</strong> should be selected.</p>
+
+<p>Return<em> an array containing the index of the row, and the number of ones in it.</em></p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> mat = [[0,1],[1,0]]
+<strong>Output:</strong> [0,1]
+<strong>Explanation:</strong> Both rows have the same number of 1&#39;s. So we return the index of the smaller row, 0, and the maximum count of ones (1<code>)</code>. So, the answer is [0,1]. 
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> mat = [[0,0,0],[0,1,1]]
+<strong>Output:</strong> [1,2]
+<strong>Explanation:</strong> The row indexed 1 has the maximum count of ones <code>(2)</code>. So we return its index, <code>1</code>, and the count. So, the answer is [1,2].
+</pre>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<pre>
+<strong>Input:</strong> mat = [[0,0],[1,1],[0,0]]
+<strong>Output:</strong> [1,2]
+<strong>Explanation:</strong> The row indexed 1 has the maximum count of ones (2). So the answer is [1,2].
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>m == mat.length</code>&nbsp;</li>
+	<li><code>n == mat[i].length</code>&nbsp;</li>
+	<li><code>1 &lt;= m, n &lt;= 100</code>&nbsp;</li>
+	<li><code>mat[i][j]</code> is either <code>0</code> or <code>1</code>.</li>
+</ul>