deploy: 638d7eb

Author: yanglbme

en/lc/184/index.html

@@ -91317,7 +91317,7 @@ <h2 id="solutions">Solutions</h2>
 
 <h3 id="solution-1-equi-join-subquery">Solution 1: Equi-Join + Subquery</h3>
 <p>We can use an equi-join to join the <code>Employee</code> table and the <code>Department</code> table based on <code>Employee.departmentId = Department.id</code>, and then use a subquery to find the highest salary for each department. Finally, we can use a <code>WHERE</code> clause to filter out the employees with the highest salary in each department.</p>
-<div class="tabbed-set tabbed-alternate" data-tabs="1:1"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">MySQL</label></div>
+<div class="tabbed-set tabbed-alternate" data-tabs="1:2"><input checked="checked" id="__tabbed_1_1" name="__tabbed_1" type="radio" /><input id="__tabbed_1_2" name="__tabbed_1" type="radio" /><div class="tabbed-labels"><label for="__tabbed_1_1">MySQL</label><label for="__tabbed_1_2">Python3</label></div>
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@@ -91343,6 +91343,48 @@ <h3 id="solution-1-equi-join-subquery">Solution 1: Equi-Join + Subquery</h3>
 <span class="w">    </span><span class="p">);</span>
 </code></pre></div></td></tr></table></div>
 </div>
+<div class="tabbed-block">
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+<span class="normal">20</span></pre></div></td><td class="code"><div><pre><span></span><code><span class="kn">import</span><span class="w"> </span><span class="nn">pandas</span><span class="w"> </span><span class="k">as</span><span class="w"> </span><span class="nn">pd</span>
+
+
+<span class="k">def</span><span class="w"> </span><span class="nf">department_highest_salary</span><span class="p">(</span>
+    <span class="n">employee</span><span class="p">:</span> <span class="n">pd</span><span class="o">.</span><span class="n">DataFrame</span><span class="p">,</span> <span class="n">department</span><span class="p">:</span> <span class="n">pd</span><span class="o">.</span><span class="n">DataFrame</span>
+<span class="p">)</span> <span class="o">-&gt;</span> <span class="n">pd</span><span class="o">.</span><span class="n">DataFrame</span><span class="p">:</span>
+    <span class="c1"># Merge the two tables on departmentId and department id</span>
+    <span class="n">merged</span> <span class="o">=</span> <span class="n">employee</span><span class="o">.</span><span class="n">merge</span><span class="p">(</span><span class="n">department</span><span class="p">,</span> <span class="n">left_on</span><span class="o">=</span><span class="s1">&#39;departmentId&#39;</span><span class="p">,</span> <span class="n">right_on</span><span class="o">=</span><span class="s1">&#39;id&#39;</span><span class="p">)</span>
+
+    <span class="c1"># Find the maximum salary for each department</span>
+    <span class="n">max_salaries</span> <span class="o">=</span> <span class="n">merged</span><span class="o">.</span><span class="n">groupby</span><span class="p">(</span><span class="s1">&#39;departmentId&#39;</span><span class="p">)[</span><span class="s1">&#39;salary&#39;</span><span class="p">]</span><span class="o">.</span><span class="n">transform</span><span class="p">(</span><span class="s1">&#39;max&#39;</span><span class="p">)</span>
+
+    <span class="c1"># Filter employees who have the highest salary in their department</span>
+    <span class="n">top_earners</span> <span class="o">=</span> <span class="n">merged</span><span class="p">[</span><span class="n">merged</span><span class="p">[</span><span class="s1">&#39;salary&#39;</span><span class="p">]</span> <span class="o">==</span> <span class="n">max_salaries</span><span class="p">]</span>
+
+    <span class="c1"># Select required columns and rename them</span>
+    <span class="n">result</span> <span class="o">=</span> <span class="n">top_earners</span><span class="p">[[</span><span class="s1">&#39;name_y&#39;</span><span class="p">,</span> <span class="s1">&#39;name_x&#39;</span><span class="p">,</span> <span class="s1">&#39;salary&#39;</span><span class="p">]]</span><span class="o">.</span><span class="n">copy</span><span class="p">()</span>
+    <span class="n">result</span><span class="o">.</span><span class="n">columns</span> <span class="o">=</span> <span class="p">[</span><span class="s1">&#39;Department&#39;</span><span class="p">,</span> <span class="s1">&#39;Employee&#39;</span><span class="p">,</span> <span class="s1">&#39;Salary&#39;</span><span class="p">]</span>
+
+    <span class="k">return</span> <span class="n">result</span>
+</code></pre></div></td></tr></table></div>
+</div>
 </div>
 </div>
 <!-- solution:end -->
@@ -91424,6 +91466,11 @@ <h3 id="solution-2-equi-join-window-function">Solution 2: Equi-Join + Window Fun
 
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@@ -91439,12 +91486,13 @@ <h3 id="solution-2-equi-join-window-function">Solution 2: Equi-Join + Window Fun
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+        
+          <a href="https://github.com/doocs/leetcode/blob/main/solution/0100-0199/0184.Department%20Highest%20Salary/README_EN.md" class="md-author md-author--more">
+            +1
+          </a>
+        
 
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