diff --git a/solution/1900-1999/1954.Minimum Garden Perimeter to Collect Enough Apples/README_EN.md b/solution/1900-1999/1954.Minimum Garden Perimeter to Collect Enough Apples/README_EN.md
index 3461a89b66e0e..f671362e0b793 100644
--- a/solution/1900-1999/1954.Minimum Garden Perimeter to Collect Enough Apples/README_EN.md	
+++ b/solution/1900-1999/1954.Minimum Garden Perimeter to Collect Enough Apples/README_EN.md	
@@ -68,6 +68,31 @@ The perimeter is 2 * 4 = 8.
 
 ## Solutions
 
+### Find the math formula for the number of apples inside a square with a side length L:
+
+Let r be the radius, which is half the side length of the square area, there're apples planted along its perimeter:
+
+-   4 corners, each corner is $|r| + |r| = 2|r|$, so $8|r|$
+-   middle top and middle bottom (when x axis = 0), each $|0| + |r| = |r|$, so $2|r|$
+-   middle left and middle right (when y axis = 0), each $|0| + |r| = |r|$, so $2|r|$
+-   between middle-top and top-right conner([1,r], [2,r], ..., [r-1,r]):
+
+    $|r-1||r| + (1 + 2 + ... + r-1) = |r-1||r| + |r||r-1|/2$
+
+    And we have 8 of them: middle-top to top-left, middle-left to top-left, ...
+
+    So we have: $8(|r-1||r| + |r||r-1|/2)$
+
+=> the total number of apples around the perimeter is:
+
+$8|r| + 4|r| + 8|r-1||r| + 4|r||r-1|
+= 12|r| + 8r^2 - 8|r| + 4r^2 - 4|r|
+= 12r^2$
+
+So the sum of apples inside a square with a side length L ($r = L/2$, perimeter = $L*4 = r*8$):
+
+$$12\left( \sum_{k=1}^r k^2 \right) = 12\left(r(r+1)(2r+1)/6\right) = 2r(r+1)(2r+1)$$
+
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 ### Solution 1