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+---
+comments: true
+difficulty: 简单
+edit_url: https://github.com/doocs/leetcode/edit/main/solution/3200-3299/3246.Premier%20League%20Table%20Ranking/README.md
+---
+
+
+
+# [3246. 英超积分榜排名 🔒](https://leetcode.cn/problems/premier-league-table-ranking)
+
+[English Version](/solution/3200-3299/3246.Premier%20League%20Table%20Ranking/README_EN.md)
+
+## 题目描述
+
+
+
+表：TeamStats
+
+
++------------------+---------+
+| Column Name | Type |
++------------------+---------+
+| team_id | int |
+| team_name | varchar |
+| matches_played | int |
+| wins | int |
+| draws | int |
+| losses | int |
++------------------+---------+
+team_id 是这张表的唯一主键。
+这张表包含队伍 id，队伍名，场次，赢局，平局和输局。
+
+
+编写一个解决方啊来计算联盟中每支球队的 得分 和 排名。积分计算方式如下：
+
+
+ - 赢局 有
3 点得分
+ - 平局 有
1 点得分
+ - 输局 有
0 点得分
+
+
+注意：积分相同的球队必须分配相同的排名。
+
+返回结果表以 points 降序 排序，然后以 team_name 升序 排序。
+
+结果格式如下所示。
+
+
+
+示例：
+
+
+
输入：
+
+
TeamStats 表：
+
+
++---------+-----------------+----------------+------+-------+--------+
+| team_id | team_name | matches_played | wins | draws | losses |
++---------+-----------------+----------------+------+-------+--------+
+| 1 | Manchester City | 10 | 6 | 2 | 2 |
+| 2 | Liverpool | 10 | 6 | 2 | 2 |
+| 3 | Chelsea | 10 | 5 | 3 | 2 |
+| 4 | Arsenal | 10 | 4 | 4 | 2 |
+| 5 | Tottenham | 10 | 3 | 5 | 2 |
++---------+-----------------+----------------+------+-------+--------+
+
+
+
输出：
+
+
++---------+-----------------+--------+----------+
+| team_id | team_name | points | position |
++---------+-----------------+--------+----------+
+| 2 | Liverpool | 20 | 1 |
+| 1 | Manchester City | 20 | 1 |
+| 3 | Chelsea | 18 | 3 |
+| 4 | Arsenal | 16 | 4 |
+| 5 | Tottenham | 14 | 5 |
++---------+-----------------+--------+----------+
+
+
+
解释：
+
+
+ - 曼城和利物浦均拿下 20 分（6 赢 * 3 分 + 2 平 * 1 分），所以他们并列第一。
+ - 切尔西拿下 18 分（5 赢 * 3 分 + 3 平 * 1 分）所以位列第三。
+ - 阿森纳拿下 16 分（4 赢 * 3 分 + 4 平 * 1 分）位列第四。
+ - 托特纳姆热刺队拿下 14 分（3 赢 * 3 分 + 5 平 * 1 分）位列第五。
+
+
+
输出表以得分降序排序，然后以 team_name 升序排序。
+
Table: TeamStats
+
+
++------------------+---------+
+| Column Name | Type |
++------------------+---------+
+| team_id | int |
+| team_name | varchar |
+| matches_played | int |
+| wins | int |
+| draws | int |
+| losses | int |
++------------------+---------+
+team_id is the unique key for this table.
+This table contains team id, team name, matches_played, wins, draws, and losses.
+
+
+Write a solution to calculate the points and rank for each team in the league. Points are calculated as follows:
+
+
+ 3 points for a win1 point for a draw0 points for a loss
+
+Note: Teams with the same points must be assigned the same rank.
+
+Return the result table ordered by points in descending, and then by team_name in ascending order.
+
+The query result format is in the following example.
+
+
+Example:
+
+
+
Input:
+
+
TeamStats table:
+
+
++---------+-----------------+----------------+------+-------+--------+
+| team_id | team_name | matches_played | wins | draws | losses |
++---------+-----------------+----------------+------+-------+--------+
+| 1 | Manchester City | 10 | 6 | 2 | 2 |
+| 2 | Liverpool | 10 | 6 | 2 | 2 |
+| 3 | Chelsea | 10 | 5 | 3 | 2 |
+| 4 | Arsenal | 10 | 4 | 4 | 2 |
+| 5 | Tottenham | 10 | 3 | 5 | 2 |
++---------+-----------------+----------------+------+-------+--------+
+
+
+
Output:
+
+
++---------+-----------------+--------+----------+
+| team_id | team_name | points | position |
++---------+-----------------+--------+----------+
+| 2 | Liverpool | 20 | 1 |
+| 1 | Manchester City | 20 | 1 |
+| 3 | Chelsea | 18 | 3 |
+| 4 | Arsenal | 16 | 4 |
+| 5 | Tottenham | 14 | 5 |
++---------+-----------------+--------+----------+
+
+
+
Explanation:
+
+
+ - Manchester City and Liverpool both have 20 points (6 wins * 3 points + 2 draws * 1 point), so they share position 1.
+ - Chelsea has 18 points (5 wins * 3 points + 3 draws * 1 point) and is position 3rd.
+ - Arsenal has 16 points (4 wins * 3 points + 4 draws * 1 point) and is position 4th.
+ - Tottenham has 14 points (3 wins * 3 points + 5 draws * 1 point) and is position 5th.
+
+
+
The output table is ordered by points in descending order, then by team_name in ascending order.
+