Make lscpu call language-invariant, fix #2577

Author: AndreyAkinshin

src/BenchmarkDotNet/Helpers/ProcessHelper.cs

@@ -12,7 +12,8 @@ internal static class ProcessHelper
         /// Run external process and return the console output.
         /// In the case of any exception, null will be returned.
         /// </summary>
-        internal static string? RunAndReadOutput(string fileName, string arguments = "", ILogger? logger = null)
+        internal static string? RunAndReadOutput(string fileName, string arguments = "", ILogger? logger = null,
+            Dictionary<string, string>? environmentVariables = null)
         {
             var processStartInfo = new ProcessStartInfo
             {
@@ -24,6 +25,9 @@ internal static class ProcessHelper
                 RedirectStandardOutput = true,
                 RedirectStandardError = true
             };
+            if (environmentVariables != null)
+                foreach (var variable in environmentVariables)
+                    processStartInfo.Environment[variable.Key] = variable.Value;
             using (var process = new Process { StartInfo = processStartInfo })
             using (new ConsoleExitHandler(process, logger ?? NullLogger.Instance))
             {

src/BenchmarkDotNet/Portability/Cpu/Linux/LinuxCpuInfoDetector.cs

@@ -1,4 +1,5 @@
-using BenchmarkDotNet.Helpers;
+using System.Collections.Generic;
+using BenchmarkDotNet.Helpers;
 
 namespace BenchmarkDotNet.Portability.Cpu.Linux;
 
@@ -14,8 +15,16 @@ internal class LinuxCpuInfoDetector : ICpuInfoDetector
     {
         if (!IsApplicable()) return null;
 
+        // lscpu output respects the system locale, so we should force language invariant environment for correct parsing
+        var languageInvariantEnvironment = new Dictionary<string, string>
+        {
+            ["LC_ALL"] = "C",
+            ["LANG"] = "C",
+            ["LANGUAGE"] = "C"
+        };
+
         string cpuInfo = ProcessHelper.RunAndReadOutput("cat", "/proc/cpuinfo") ?? "";
-        string lscpu = ProcessHelper.RunAndReadOutput("/bin/bash", "-c \"lscpu\"");
+        string lscpu = ProcessHelper.RunAndReadOutput("/bin/bash", "-c \"lscpu\"", environmentVariables: languageInvariantEnvironment);
         return LinuxCpuInfoParser.Parse(cpuInfo, lscpu);
     }
 }