Object initializer syntax: anonymous types vs actual types

[TonyValenti]

Right now I an create an anonymous type like so:

            var Start = 1;
            var B = new {
                Start,
                End = 100
            };

When I create a regular type, I can't do that though and have to specify the property name even when it matches a variable name. I should be able to do:

            var Start = 1;
            var B = new Range() {
                Start, //Currently I have to do: Start = Start
                End = 100
            };

[iam3yal]

@TonyValenti I feel like you shouldn't because in the first example you define a new property which makes more sense to me whereas in the second example you initialize an existing property so I don't know, it might be confusing to some people but then maybe it's just me.

Edit: Rephrased.

[quinmars]

That reminds me a little bit on #2616

        int Capacity = 100;
        var list = new List<int> ()
        {
            Capacity
        };

This compiles and adds the value 100 to the list.