Records: Automatically generate EqualityComparer

[TonyValenti]

Since records are already generating compare methods, it would be nice if they also automatically generated an EqualityComparer class similar to what I show below:

    public class BaseRecord {
        public static bool Equals (BaseRecord x, BaseRecord y) {
            //Code

            return true;
        }

        public override int GetHashCode() {
            return base.GetHashCode();
        }

        public class EqualityComparer : IEqualityComparer<BaseRecord> {

            public static EqualityComparer Default { get; private set; } = new EqualityComparer();

            public bool Equals([AllowNull] BaseRecord x, [AllowNull] BaseRecord y) {
                return BaseRecord.Equals(x, y);
            }

            public int GetHashCode([DisallowNull] BaseRecord obj) {
                return obj.GetHashCode();
            }
        }

    }

    public class DerivedRecord : BaseRecord {
        public static bool Equals(DerivedRecord x, DerivedRecord y) {
            //Code

            return true;
        }

        public override int GetHashCode() {
            return base.GetHashCode();
        }

        public new class EqualityComparer : IEqualityComparer<DerivedRecord> {

            public static EqualityComparer Default { get; private set; } = new EqualityComparer();

            public bool Equals([AllowNull] DerivedRecord x, [AllowNull] DerivedRecord y) {
               return DerivedRecord.Equals(x, y);
            }

            public int GetHashCode([DisallowNull] DerivedRecord obj) {
                return obj.GetHashCode();
            }
        }

    }

[theunrepentantgeek]

For any type Foo that implements IEquatable<Foo> you can use EqualityComparer<Foo>.Default to get an instance of IEqualityComparer<Foo> for that type; I don't think records need to implement their own.