Operator '==' cannot be applied to operands of type 'TProperty' and 'TProperty'

[xiaodongcool]

public interface IFoo<TProperty>
{
    public TProperty Name { get; set; }
}

public class Program<TClass, TProperty> where TClass : IFoo<TProperty>
{
    public void Main(TProperty name)
    {
        // error
        TestExpression(_ => _.Name == name);
    }

    public void TestExpression(Expression<Func<TClass, bool>>? match = null) { }
}

[FaustVX]

Because the compiler can't know if TProperty declare an == operator.
You can do _ => _.Name.Equals(name)

[tfenise]

or _ => System.Collections.Generic.EqualityComparer<TProperty>.Default.Equals(_.Name, name), which is generic and may eliminate boxing for value types.

[Joe4evr]

It's not just that it'd remove boxing, but if the JIT sees the full expression of EqualityComparer<T>.Default.Equals(x, y) it will simply emit the same asm as it would have for x == y.