Fix typo "curent" (#10417)

* Fixed typo in xat.vb

* Fix typo in csharp's xat.cs

* Create Project.csproj for SecureString/AppendChar

* Update xat.cs

* Create Project.vbproj for visualbasic/VS_Snippets_CLR/SecureString

Author: makazeu

snippets/csharp/System.Security/SecureString/AppendChar/Project.csproj

@@ -0,0 +1,8 @@
+<Project Sdk="Microsoft.NET.Sdk">
+
+  <PropertyGroup>
+    <OutputType>Library</OutputType>
+    <TargetFramework>net6.0</TargetFramework>
+  </PropertyGroup>
+   
+</Project>

snippets/csharp/System.Security/SecureString/AppendChar/xat.cs

@@ -2,11 +2,11 @@
 using System;
 using System.Security;
 
-class Example
+class SecureStringExample
 {
     public static void Main()
     {
-       string msg = "The curent length of the SecureString object: {0}\n";
+       string msg = "The current length of the SecureString object: {0}\n";
        Console.WriteLine("1) Instantiate the SecureString object.");
        SecureString ss = new SecureString();
        Console.WriteLine(msg, ss.Length);
@@ -44,26 +44,26 @@ public static void Main()
 }
 // The example displays the following output:
 //       1) Instantiate the SecureString object.
-//       The curent length of the SecureString object: 0
+//       The current length of the SecureString object: 0
 //
 //       2) Append 'a' to the value.
-//       The curent length of the SecureString object: 1
+//       The current length of the SecureString object: 1
 //
 //       3) Append 'X' to the value.
-//       The curent length of the SecureString object: 2
+//       The current length of the SecureString object: 2
 //
 //       4) Append 'c' to the value.
-//       The curent length of the SecureString object: 3
+//       The current length of the SecureString object: 3
 //
 //       5) Insert 'd' at the end of the value.
-//       The curent length of the SecureString object: 4
+//       The current length of the SecureString object: 4
 //
 //       6) Remove the last character ('d') from the value.
-//       The curent length of the SecureString object: 3
+//       The current length of the SecureString object: 3
 //
 //       7) Set the second character of the value to 'b'.
-//       The curent length of the SecureString object: 3
+//       The current length of the SecureString object: 3
 //
 //       8) Delete the value of the SecureString object:
-//       The curent length of the SecureString object: 0
-//</snippet1>
+//       The current length of the SecureString object: 0
+//</snippet1>

snippets/visualbasic/VS_Snippets_CLR/SecureString.xAt/VB/Project.vbproj

@@ -0,0 +1,8 @@
+<Project Sdk="Microsoft.NET.Sdk">
+
+  <PropertyGroup>
+    <OutputType>Exe</OutputType>
+    <TargetFramework>net6.0</TargetFramework>
+  </PropertyGroup>
+
+</Project>

snippets/visualbasic/VS_Snippets_CLR/SecureString.xAt/VB/xat.vb

@@ -3,7 +3,7 @@ Imports System.Security
 
 Module Example
     Public Sub Main()
-       Dim msg As String = "The curent length of the SecureString object: {0}" + vbCrLf
+       Dim msg As String = "The current length of the SecureString object: {0}" + vbCrLf
        Console.WriteLine("1) Instantiate the SecureString object.")
        Dim ss As New SecureString()
        Console.WriteLine(msg, ss.Length)
@@ -41,26 +41,26 @@ Module Example
 End Module
 ' The example displays the following output:
 '       1) Instantiate the SecureString object.
-'       The curent length of the SecureString object: 0
+'       The current length of the SecureString object: 0
 '
 '       2) Append 'a' to the value.
-'       The curent length of the SecureString object: 1
+'       The current length of the SecureString object: 1
 '
 '       3) Append 'X' to the value.
-'       The curent length of the SecureString object: 2
+'       The current length of the SecureString object: 2
 '
 '       4) Append 'c' to the value.
-'       The curent length of the SecureString object: 3
+'       The current length of the SecureString object: 3
 '
 '       5) Insert 'd' at the end of the value.
-'       The curent length of the SecureString object: 4
+'       The current length of the SecureString object: 4
 '
 '       6) Remove the last character ('d') from the value.
-'       The curent length of the SecureString object: 3
+'       The current length of the SecureString object: 3
 '
 '       7) Set the second character of the value to 'b'.
-'       The curent length of the SecureString object: 3
+'       The current length of the SecureString object: 3
 '
 '       8) Delete the value of the SecureString object:
-'       The curent length of the SecureString object: 0
-'</snippet1>
+'       The current length of the SecureString object: 0
+'</snippet1>