Memory Allocation Query

[AubsUK]

Looking at settings.c, and part of the SETTINGS_FactoryReset function:

(
	!(i >= 0x0D60 && i < 0x0E28) &&     // MR Channel Attributes
	!(i >= 0x0F18 && i < 0x0F30) &&     // Scan List
	!(i >= 0x0F50 && i < 0x1C00) &&     // MR Channel Names
	!(i >= 0x0E40 && i < 0x0E70) &&     // FM Channels
	!(i >= 0x0E88 && i < 0x0E90)        // FM settings
)

That matches with one section in the SETTINGS_InitEEPROM function also in settings.c:

// 0D60..0E27
EEPROM_ReadBuffer(0x0D60, gMR_ChannelAttributes, sizeof(gMR_ChannelAttributes));

Except the following declaration from misc.h indicates each channel att contains 2 bytes:

typedef union {
    struct {
        uint8_t
            band : 4,
            compander : 2,
            scanlist2 : 1,
            scanlist1 : 1;
    };
    uint8_t __val;
} ChannelAttributes_t;

and the declaration also in misc.h indicates there's 207 of them:

extern ChannelAttributes_t   gMR_ChannelAttributes[207];

Surely that would mean it needs 207 objects * 2 bytes each = 414 bytes, but 0D60..0E27 represents 3424..3623 = 200 bytes - One for each channel, not the required two.

But then also in the SETTINGS_InitEEPROM function in settings.c:

	for(uint16_t i = 0; i < sizeof(gMR_ChannelAttributes); i++) {

Doesn't that mean it reads 16-bit (2 bytes) for each channel?

I'm clearly missing something, could someone help clarify this for me please?

[egzumer]

Attributes are one byte long.
207 is 200 channels + 7 bands in frequency mode

UV K5 EEPROM.ods

[AubsUK]

The memory space map is really useful thank you.

I realise I was wrong because the struct { band / compander / scanlist2 / scanlist1 } and __val occupy the same 8-bit memory location.