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Composing schemas #37

@edkelly303

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@edkelly303

Thank you so much for this library!

I'm not sure if I just missed this, or if it's a bad idea, or if there's a better way to achieve it - but does Norm include an "and" for specs/schemas, corresponding to the "or" provided by one_of?

For example, say I have two schemas like:

quick_checks = schema(%{
  id: spec(is_integer()), 
  name: spec(is_string())
})

expensive_checks = schema(%{
  id: spec(some_complex_calculation()),
  age: spec(another_complex_calculation())
})

Perhaps most of the time I only want to do the quick_checks, but on some occasions I want to do ALL the checks. Is there (/should there be) a way to compose the two schemas so that I end up with something like the following?

all_checks = schema(%{
  id: spec(is_integer() and some_complex_calculation()), 
  name: spec(is_string()), 
  age: spec(another_complex_calculation())
})

I guess if you're using conform!/2 it doesn't really matter, because you can just do

data 
|> conform!(quick_checks) 
|> conform!(expensive_checks)

and you'll get an exception if something goes wrong.

But with conform/2 it's a bit trickier if you want to catch all the validation errors in one output. I wrote a helper function called conform_all, but it doesn't seem like a very elegant approach.

def conform_all(input, specs_and_schemas) do
  Enum.reduce(specs_and_schemas, {:ok, input}, fn spec_or_schema, previous_result ->
    case previous_result do
      {:ok, input} ->
        case conform(input, spec_or_schema) do
          {:ok, input} -> {:ok, input}
          {:error, new_errors} -> {:error, new_errors}
        end

      {:error, existing_errors} ->
        case conform(input, spec_or_schema) do
          {:ok, _input} -> {:error, existing_errors}
          {:error, new_errors} -> {:error, existing_errors ++ new_errors}
        end
    end
  end)
end

Apologies if I'm missed something obvious, and thanks so much again for Norm!

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